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3 years ago

What is the [OH-] in a solution if the [H*] = 1.2 x 10-3 M?

Chemistry

1 answer:

spayn [35]3 years ago

7 0

We know that [OH⁻] * [H⁺] = 10⁻¹⁴

plugging the value of [H⁺]

[OH⁻] * 1.2 * 10⁻³ = 10⁻¹⁴

[OH⁻] = 10⁻¹⁴ * (10³/1.2)

[OH⁻] = 833.3 * 10⁻¹⁴

[OH⁻] = 8.33 * 10⁻¹²

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g At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H 2 (g) Br 2 (g)

oksano4ka [1.4K]

Answer: At equilibrium , there are 0.274 moles of $Br_2$

Explanation:

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The given balanced equilibrium reaction is,

$H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)$

Initial conc. 0.341 M 0.220 M 0 M

At eqm. conc. (0.341-x) M (0.220-x) M (2x) M

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x= 0.083 M

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3 years ago

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4 years ago

Read 2 more answers

A sheet of aluminum foil has a total area of 1.000 m2 and a mass of 3.636 g. What is the thickness of the sheet in millimeters?

olga2289 [7]

Answer:

$t=1.34\times 10^{-3}\ mm$

Explanation:

Given that,

Area of sheet of Aluminium foil is 1 m²

Mass of the sheet = 3.636 g

The density of Aluminium, $d=2.699\ g/cm^3$

We need to find the thickness of the sheet in millimeters.

The density of an object is given in terms of its mass and volume as follows :

$d=\dfrac{m}{V}$

V = volume, V = A×t, t = thickness of the sheet

So,

$d=\dfrac{m}{A\times t}\\\\t=\dfrac{m}{Ad}\\\\t=\dfrac{3.636\ g}{10000\ cm^2\times 2.699\ g/cm^3}\\\\t=0.000134\ cm$

Since, 1 cm = 10 mm

So,

t = 0.00134 mm

$t=1.34\times 10^{-3}\ mm$

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3 years ago