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PolarNik [594]
3 years ago
6

The number main-group elements'valance electrons can be determined by____ on the periodic table​

Chemistry
1 answer:
Zanzabum3 years ago
7 0
<h2>Answer:</h2>

Valance electrons can be determined by <u>Group</u> on the periodic table​

<h2>Explanation:</h2>
  • Valence electrons are the electrons present in the outermost shell of an atom. We can determine the total number of valence electrons present in an atom by checking at its Group in which it is placed in the periodic table. For example, atoms in Groups 1 the number of valence electron is one and for group 2 the number of valence electrons is 2.
  • The groups have number of valance electrons as follow:

Group 1 - 1 valence electron.

Group 2 - 2 valance electrons.

Group 13 - 3 valence electrons.

Group 14 - 4 valance electrons.

Group 15 - 5 valence electrons.

Group 16 - 6 valence electrons.

Group 17 - 7 valence electrons.

Group 18 - 8 valence electrons.

Result: No of valence electron can be determined by the group no. of the element.

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Which of the following is ranked from smallest to largest?
Nuetrik [128]

Answer:

The order is: electron, carbon, water,  glucose, glycogen.    

Explanation:

The electron is a negatively charged subatomic particle and is therefore the smallest.

Carbon is a chemical element, which belongs to the group-14 of periodic table and has atomic number 6.

Water is a odorless, almost colorless and tasteless chemical compound which is necessary for all the known living form. The chemical formula is H2O and it is composed of 2 hydrogen atoms and one oxygen atom.

Glucose is a monosaccharide sugar and a type of simple carbohydrate. The chemical formula is C6H12O6 and is composed of 6 carbon atoms, 6 oxygen atoms and 12 hydrogen atoms.

Glycogen is a branched polysaccharide molecule, which is composed of multiple monomeric glucose units. Therefore, it is the largest.

<u>Therefore, the increasing order is: electron, carbon, water,  glucose, glycogen.</u>

3 0
3 years ago
If a wave has a frequency of 2.85x10^10 its wavelength is ?
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Answer:

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3 0
3 years ago
Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?
Naddika [18.5K]
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
7 0
3 years ago
How much heat is required to raise the temperature of 50.0g of water 13°C<br>​
N76 [4]

Answer:one gram by 1oC

Explanation: you will need to know the value of water's specific heat

3 0
3 years ago
An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
san4es73 [151]

Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

                 the anion )

0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

Therefore,  the ionic radius of the anion r^- = 312.52 \ pm

4 0
3 years ago
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