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PolarNik [594]
2 years ago
6

The number main-group elements'valance electrons can be determined by____ on the periodic table​

Chemistry
1 answer:
Zanzabum2 years ago
7 0
<h2>Answer:</h2>

Valance electrons can be determined by <u>Group</u> on the periodic table​

<h2>Explanation:</h2>
  • Valence electrons are the electrons present in the outermost shell of an atom. We can determine the total number of valence electrons present in an atom by checking at its Group in which it is placed in the periodic table. For example, atoms in Groups 1 the number of valence electron is one and for group 2 the number of valence electrons is 2.
  • The groups have number of valance electrons as follow:

Group 1 - 1 valence electron.

Group 2 - 2 valance electrons.

Group 13 - 3 valence electrons.

Group 14 - 4 valance electrons.

Group 15 - 5 valence electrons.

Group 16 - 6 valence electrons.

Group 17 - 7 valence electrons.

Group 18 - 8 valence electrons.

Result: No of valence electron can be determined by the group no. of the element.

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4 0
3 years ago
Which of the following represents the least number of molecues?
Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

Best of luck.

7 0
2 years ago
PLEASE ANSWER + BRAINLIEST !!!
MA_775_DIABLO [31]
Hope this would help you

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