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ehidna [41]
2 years ago
6

Sdfsdfsdfsfsdfsdfdfdre

Chemistry
1 answer:
frez [133]2 years ago
7 0

Answer:

310 mmHg

Explanation:

All you have to do here in order to figure out the pressure exerted by gas  

D  is use Dalton's Law of Partial Pressures.

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Can isotopes have different atomic numbers
Tpy6a [65]

Answer:

No

Explanation:

Atomic number represents the identity of atoms

using number of protons which is equal in isotopes.

6 0
3 years ago
The question in the picture, I really a correct answer, no cheap answers​
Delvig [45]

Answer:

94.325 g

Explanation:

We'll begin by converting 350 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

350 mL = 350 mL × 1 L /1000 mL

350 mL = 0.35 L

Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:

Volume = 0.35 L

Molarity of KC₂H₃O₂ = 2.75 M

Mole of KC₂H₃O₂ =?

Molarity = mole /Volume

2.75 = Mole of KC₂H₃O₂ / 0.35

Cross multiply

Mole of KC₂H₃O₂ = 2.75 × 0.35

Mole of KC₂H₃O₂ = 0.9625 mole

Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:

Mole of KC₂H₃O₂ = 0.9625 mole

Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)

= 39 + 24 + 3 + 32

= 98 g/mol

Mass of KC₂H₃O₂ =?

Mass = mole × molar mass

Mass of KC₂H₃O₂ = 0.9625 × 98

Mass of KC₂H₃O₂ = 94.325 g

Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g

6 0
2 years ago
Which of the following is an example of a “nature vs. nurture" question?
Naily [24]

Answer:

The answer to your question is D

5 0
3 years ago
Which is the best revision of this sentence?
taurus [48]
Give more points, dont even feel like reading this for 5 pointsssss
3 0
2 years ago
What is the molarity of the solution produced when 8.0g NaOH is dissolved in sufficient water to prepare 500.mL of solution?
Sindrei [870]

Answer:

Molarity = 0.4M

Explanation:

Molar mass of NaOH (M)= 40

m= 8g, V= 500ml=0.5L

n= m/M=[8/40]= 0.2mol

Applying

n= CV

0.2= C×0.5

C= 0.4M

8 0
3 years ago
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