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3 years ago

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Chemistry

1 answer:

frez [133]3 years ago

7 0

Answer:

310 mmHg

Explanation:

All you have to do here in order to figure out the pressure exerted by gas

D is use Dalton's Law of Partial Pressures.

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Henry’s law is important in environmental chemistry, where it predicts the distribution of pollutants between water and the atmo

lina2011 [118]

Answer:

Explanation:

Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid

number of moles of cyclopropane = 1.84 g / 42.08 g/mol = 0.044 mol

number of mole of water = 1010000 g / 18.02 g/mol = 56048.83 mol

mole fraction of cyclopropane = mole of cyclopropane / ( mole of water + mole of cyclopropane) = 0.044 mol / 56048.87 = 7.85 × 10⁻⁷

P cyclopropane = k henry × mole fraction of cyclopropane = 4273 atm × 7.85 × 10⁻⁷ = 0.00335 atm

b) number of cyclopropane molecules present in each cubic centimeter = ( 0.044 mol / 1010) × 6.022 × 10 ²³ / 1000 cm³ = 2.623 × 10 ¹⁶ molecules in cm³

8 0

3 years ago

The reference compound for naming d and l isomers of sugars is

Vladimir [108]

Your answer would be GLYCERALDEHYDE.

Hope that helps!!!!

8 0

3 years ago

Liquid A is poured into Liquid B and a single, clear layer results. More Liquid A is added and two distinct layers form. The sol

pogonyaev

Answer:

Explanation:

Liquid A is poured into Liquid B and a single, clear layer results. More Liquid A is added and two distinct layers form. The solution is now unsaturated and there is a static equilibria occurring

4 0

3 years ago

b. How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda?

vredina [299]

74.4 ml of millimeters needed to react with 15 grams of baking soda

<u>Explanation:</u>

Given data

n C8 H8 07= 0.8 M

m NaHCO3=15 g

<u>Solving the problem:</u>

From the equation we get,

3x C6 H8 07 = NaHC03

Finding the molar mass for the baking soda

NaHCO3= 23+1+12+3 x16= 84 g / mol

so,

n NaHCO3= m NaHCO3/ M NaHCO3

And then,

n C6 H8 07 =1/3 × n NaHCO3

From the definition of the molarity we get

V C6 H8 O 7=n C6 H8 07/C6 H8 07

=n NaHCO3/3 × C6 H8 07 =

m NaHCO3/ M NaHCO3/ 3 × C6 H8 07

Calculating the equation we get,

V C6 H8 O 7= 15/84/3 ×0.8=5/84 ×0.8= 0.0744L= 74.4 ml

74.4 ml of millimeters needed to react with 15 grams of baking soda

n C8 H8 07= 0.8 M

m NaHCO3=15 g

Solving the problem:

From the equation we get,

3x C6 H8 07 = NaHC03

Finding the molar mass for the baking soda

Nahco3= 23+1+12+3 x16= 84 g / mol

so,

n NaHCO3= m NaHCO3/ M NaHCO3

And then,

n C6 H8 07 =1/3 × n NaHCO3

From the definition of the molarity we get

V C6 H8 O 7=n C6 H8 07/C6 H8 07

=n NaHCO3/3 × C6 H8 07 =

m NaHCO3/ M NaHCO3/ 3 × C6 H8 07

Calculating the equation we get,

V C6 H8 O 7= 15/84/3 ×0.8=5/84 ×0.8= 0.0744L= 74.4 ml

74.4 ml of millimeters needed to react with 15 grams of baking soda

4 0

4 years ago

A 60g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43g lead, 17.83g carbon and 3.74g hydrogen. Determi

anastassius [24]

Answer:

Empirical formula (which matches the molecular formula) is = PbC₈H₂₀

Explanation:

Our sample: 60 g of tetraethyl lead

In order to determine the compound empirical formula we need the centesimal composition:

(Mass of element / Total mass) . 100 =

(38.43 g lead / 60g ) . 100 = 64.05%

(17.83 g C / 60g) . 100 = 29.72%

(3.74 g H / 60g) . 100 = 6.23 %

These % are the mass of the elements in 100 g of compound. Let's find out the moles of them:

64.05 g / 207.2 g/mol = 0.309 moles

29.72 g / 12 g/mol = 2.48 moles

6.23 g/ 1 g/mol = 6.23 moles

Next, we divide the moles, by the lowest value of them (0.309)

0.309 / 0.309 = 1 mol Pb

2.48 / 0.309 = 8 mol C

6.23 / 0.309 = 20 mol H

There, we have our formula PbC₈H₂₀

6 0

4 years ago