Please show work, im really confused so please help!!

Chemistry

1 answer:

Rama09 [41]3 years ago

4 0

No because the mass of the empty beaker , mass of beaker is not balanced the amount of alcohol in the beaker.

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A woman with diagnosed osteoporosis is told by her doctor to take 1,000 mg of calcium carbonate in addition to increasing intake

spayn [35]

Answer:

400 mg

Explanation:

Given:

A woman with is told by her doctor to take 1,000 mg of calcium carbonate.

Question asked:

How many mg of calcium are in this 1,000 mg regimen of calcium carbonate?

Solution:

As we know:

<em>Amount of elemental calcium in a medicine containing calcium carbonate = 40%</em>

As here doctor prescribed 1000 mg of calcium carbonate to be taken by the woman increasing intake of calcium-containing foods in her diet and including regular weight-bearing exercise, hence amount of elemental calcium in 1,000 mg regimen of calcium carbonate will be,

$40\%\ of\ 1000\ mg\\\frac{40}{100} \times1000\ mg\\\frac{40000}{100} = 400\ mg$

Therefore, 400 mg of calcium are in this 1,000 mg regimen of calcium carbonate.

6 0

4 years ago

A 100g of sample of a compound is combusted in excess oxygen and the products are 2.492g of CO2 and 0.6495 of H2O. Determine the

ruslelena [56]

The empirical formula : C₁₁O₁₄O₃

<h3>Further explanation</h3>

The assumption of the compound consists of C, H, and O

mass of C in CO₂ =

$\tt \dfrac{12}{44}\times 2.492=0.680~g$

mass of H in H₂O =

$\tt \dfrac{2.1}{18}\times 0.6495=0.072~g$

mass of O :

mass sample-(mass C + mass H)

$\tt 1-(0.68+0.072)=0.248`g$

mol of C :

$\tt \dfrac{0.68}{12}=0.056$

mol of H :

$\tt \dfrac{0.072}{1}=0.072$

mol of O :

$\tt \dfrac{0.248}{16}=0.0155$

divide by 0.0155(the lowest ratio)

C : H : O ⇒

$\tt \dfrac{0.056}{0.0155}\div \dfrac{0.072}{0.0155}\div \dfrac{0.0155}{0.0155}=3.6\div 4.6\div 1\\\\\dfrac{11}{3}\div \dfrac{14}{3}\div \dfrac{3}{3}=11:14:3$