Answer:
Methane is a covalent bond. Methane is a chemical compound from the bonding one carbon atom and for hydrogen atoms. Although electronegativity increases as you go right of the periodic table, hydrogen has an electronegativity of 2.20. Chlorine has an electronegativity of 2.55. There difference in electron negativity (0.34). Therefore it is a non polar compound. If there difference was much greater, than they would form a ionic bond. Alkali metals tend to form the most ionic bond, but although hyrdogen is placed with them, it has a higher electronegativity so hydrogen is an exception.
Carbon has 4 valence electrons so it will want to gain 4 more electrons to become stable (Octet rule). Hydrogen has 1 valence electron, so it will want to lose it to become stable. Therefore, one carbon atom takes 1 electrons from 4 hydrogen atoms.
Because pure silicon is a perfect semiconductor.
For room temperature, it rarely conducts, you can search for the threshold temperature, the characteristic equation is fairly complicated.
An ion is an element that bears only one electric charge, either positive or negative. An isotope is an element with the same number of protons but a different number of neutrons. An electron is a negatively charged subatomic particle. A dipole fits the characteristics. Hence, the answer is B.
Answer:
The most common position for an double bond in an unsaturated fatty acid is delta 9 (Δ⁹)
Explanation:
Unsaturated fatty acids are carboxylic acids which contains one or more double bonds. The chain length as well as the number of double bonds is written separated by a colon. The positions of the double bonds are specified starting from the carboxyl carbon, numbered as 1, by superscript numbers following a delta (Δ). For example, an 18-carbon fatty acid containing a single double bond between carbon number 9 and 10 is written as 18:1(Δ⁹).
In most monounsaturated fatty acids, the double bond is between C-9 and C-10 (Δ⁹), and the other double bonds of polyunsaturated fatty acids are generally Δ¹² and Δ¹⁵. This positioning is due to the nature of the biosynthesis of fatty acids. In the mammalian hepatocytes, double bonds are introduced easily into fatty acids at the Δ⁹ position, but cannot introduce additional double bonds between C-10 and the methyl-terminal end. However, plants are able to introduce these additional double bonds at the Δ¹² and Δ¹⁵ positions.
