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sashaice [31]
3 years ago
15

Calculate the molarity of the two solutions.

Chemistry
1 answer:
beks73 [17]3 years ago
8 0

Answer:

A = Molarity = 0.22 M

B = Molarity = 0.36 M

Explanation:

Given data:

For first solution:

number of moles = 0.550 mol

Volume of solution = 2.50 L

Molarity = ?

Molarity:

Formula:

Molarity = number of moles of solute / volume of solution in L.

Molarity = 0.550 mol / 2.50 L

Molarity = 0.22 M

For second solution:

Mass of NaCl =  15.7 g

Volume of solution = 709 mL  or 709/1000 = 0.709 L

Molarity = ?

Solution:

Number of moles = mass / molar mass

Number of moles = 14.7 g/ 58.44 g/mol

Number of moles = 0.252 mol

Molarity:

Molarity = number of moles of solute / volume of solution in L.

Molarity = 0.252 mol / 0.709 L

Molarity = 0.36 M

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Answer:

there must be free-moving electrons in a compound to conduct electricity.

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In a neutral solution, the concentration of H+ is
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If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?
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Here we have to get the K_{p} of the reaction at 520 K temperature.

The K_{p} of the reaction is 1.705 atm

We know the relation between K_{p} and K_{c} is K_{p}=K_{c}(RT)^{N}, where  K_{p} = The equilibrium constant of the reaction in terms of partial pressure, K_{c}  = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.

Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of  K_{c} is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

K_{p} = 4.0 X 10^{-2}(0.082X520)^{1}

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What type of effects do prostaglandins produce on smooth muscles? List two examples.
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Answer:

\large \boxed{\text{Fe$^{{2+}}$}}

Explanation:

1. Number of electrons

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2. Number of protons

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