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3 years ago

Which weather component describes how fast the wind is moving?

Chemistry

2 answers:

Strike441 [17]3 years ago

6 0

Wind speed because speed is how fast something moves

Ivan3 years ago

4 0

Wind speed is the answer

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Given the atomic radius of xenon, 1.3 ?, and knowing that a sphere has a volume of 4?r3/3, calculate the fraction of space that

34kurt

R = 1.3 A° = 1.3 × 10^(-10) m
$v \: = \: \frac{4}{3} \pi {r}^{3}$
$v \: = \: \frac{4}{3} \times 3.1415 \times {(1.3 \times {10}^{ - 10} )}^{3}$
V = 9.20277208×10^(−30) m.

7 0

3 years ago

In calculating the relationship between the amount of heat added to a substance and the corresponding temperature change, the sp

otez555 [7]

Answer:

Explanation:

Specific heat capacity of a substance can be defined as the amount of heat a gram of the substance must lose or absorb in order to change its temperature by a degree Celsius. It is measured in Joules per kilogram per degree Celsius (J/kg°C).

Generally, the specific heat capacity of water is 4.182J/kg°C and is the highest among liquids.

Heat capacity or quantity of heat is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of the substance.

dt represents the change in temperature.

Hence in calculating the relationship between the amount of heat added to a substance and the corresponding temperature change, the specific heat capacity is usually represented by the symbol C.

6 0

3 years ago

Which element has the same number of valence electrons as oxygen. Neon sulfur fluorine nitrogen

Dovator [93]

Sulfur has the same amount, like all the other elements in group 16, has six valence electrons.

5 0

3 years ago

How do higher temperatures influence a chemical change?

Brums [2.3K]

<span>Basically, temperature changes the reaction, which means that it would be a chemical change since it changes the formation of bonds and reactions. </span>

8 0

3 years ago

Read 2 more answers

The enthalpy of reaction changes somewhat with temperature. Suppose we wish to calculate ΔH for a reaction at a temperature T th

Contact [7]

Answer:

-99.8 kJ

Explanation:

We are given the methodology to answer this question, which is basically Kirchhoff law . We just need to find the heats of formation for the reactants and products and perform the calculations.

The standard heat of reaction is

ΔrHº = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where ν are the stoichiometric coefficients in the balanced equation, and ΔfHº are the heats of formation at their standard states.

Compound ΔfHº (kJmol⁻¹)

SO₂ -296.8

O₂ 0

SO₃ -395.8

The balanced chemical equation is

SO₂(g) + ½O₂(g) → SO₃(g)

Thus

Δr, 298K Hº( kJmol⁻¹ ) = 1 x (-395.8) - 1 x (-296.8) = -99.0 kJmol⁻¹

Now the heat capacity of reaction will be be given in a similar fashion:

Cp rxn = ∑ ν x Cp of products - ∑ ν x Cp of reactants

where ν is as above the stoichiometric coefficient in the balanced chemical equation.

Cprxn ( JK⁻¹mol⁻¹) = 50.7 - ( 39.9 + 1/2 x 29.4 ) = - 3.90

= -3.90 JK⁻¹mol⁻¹

Finally Δr,500 K Hº = Δr, 298K Hº + CprxnΔT

Δr,500 K Hº = - 99 x 10³ J + (-3.90) JK⁻¹ ( 500 - 298 ) K = -99,787.8

= -99,787.8 J x 1 kJ/1000 J = -99.8 kJ

Notice thie difference is relatively small that is why in some problems it is o.k to assume the change in enthalpy is constant over a temperature range, especially if it is a small range of temperatures.

3 0

3 years ago