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sdas [7]
3 years ago
14

What machine is a seesaw mechanical compound complex simple

Physics
1 answer:
guapka [62]3 years ago
5 0
I'm pretty sure its simple! I hope this helps
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Answer: Can I get a picture???

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3 years ago
A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta
My name is Ann [436]

Answer:

a).K=528.92 \frac{N}{m}

b).m=4.84kg

Explanation:

a).

The work of the spring is find by the formula:

w_s =\frac{1}{2}*k*x^2

So knowing the work can find the constant K'

3.2J =\frac{1}{2}*k*(0.11m)^2

Solve for K'

K=\frac{2*W_s}{x^2}=\frac{2*3.2J}{0.11m^2}

K=528.92 \frac{N}{m}

b).

The force of the spring realice a motion so using the force and knowing the accelerations can find the mass

F=m*a

m=\frac{F}{a}=\frac{K*x}{a}

m=\frac{528.9*0.11m}{12m/s^2}

m=4.84kg

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3 years ago
if you push your chair across the floor at a constant velocity how does the force of friction compare with the force you exert?
Alik [6]
-- If velocity is constant, then there is no net force
on the chair.

-- If there is no net force on the chair, then friction
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-- The force of friction is exactly equal in magnitude
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In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.
garik1379 [7]

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...

Find the equivalent resistance of the right branch of the circuit:

R_{eq}  = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms

\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411

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2 years ago
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