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dsp73
3 years ago
5

What Are Some Examples of Friction in everyday life?

Physics
1 answer:
bekas [8.4K]3 years ago
3 0

Explanation:

Everyday Examples of Sliding Friction

Rubbing both hands together to create heat.

A sled sliding across snow or ice.

Skis sliding against snow.

A person sliding down a slide is an example of sliding friction.

A coaster sliding against a table.

A washing machine pushed along a floor.

An iron being pushed across material.

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An elderly sailor is shipwrecked on a desert island but manages to save his eyeglasses. The lens for one eye has a power of 1.16
igomit [66]

Answer:

m = 8

Explanation:

A telescope is a device that allows us to see objects that were very far from us, it is built by the combination of two lenses, the one with the lowest focal length near the eye and that is the one or the one with the greatest focal length, the most eye-flounder . The magnification of the telescope is

            m = - f₀ / f_{e}

Where f₀ is the focal length of the lens and f_{e} is the false distance of the eyepiece.

It is this problem that gives us the diopter of each lens, these are related to the focal length in meters

           D = 1 / f

Let's find the focal length

       f₁ = 1 / D₁

       f₁ = 1 / 1.16

       f₁ = 0.862 m

     

        f₂ = 1 / 9.37

        f₂ = 0.1067 m

Therefore, the lens with f₂ is the eyepiece and the slow one with the  

distance focal  f₁ is the objective.

Let's calculate

       m = - f₂ / f₁

      m = - 0.862 / 0.1067

      m = 8

8 0
3 years ago
How many different parts parts of the solar system can you see?
photoshop1234 [79]

Out of the solar system parts, we can see the sun, a few planets, some meteorites and comets.

Rest all is not visible through naked eyes

6 0
3 years ago
A current of 0.92 a flows in a wire. how many electrons are flowing past any point in the wire per second? the charge on one ele
Fantom [35]
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, \Delta t:
I= \frac{Q}{\Delta t}
First we need to find the net charge flowing at a certain point of the wire in one second, \Delta t=1.0 s. Using I=0.92 A and re-arranging the previous equation, we find
Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C

Now we know that each electron carries a charge of e=1.6 \cdot 10^{-19} C, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18}
3 0
3 years ago
A ______________ is very general in nature, while a ________________ specifies what we want to study more specifically, suggesti
vova2212 [387]

Answer:

research topic and research question (hypothesis)

Explanation:

6 0
3 years ago
How far away is a cliff if an echo is heard 0.486 s after the original sound? Assume that sound traveled at 343 m/s on that day.
goldfiish [28.3K]
143m/s if you just perhaps by what you know you'll figure it out
4 0
3 years ago
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