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3 years ago

What information is needed to determine the orientation of an orbital?

Physics

1 answer:

kolbaska11 [484]3 years ago

8 0

Answer:

The magnetic quantum number (l) determines the orientation of an orbital

Explanation:

The magnetic quantum number of an electron's orbital is the spatial orientation of the electron's orbital

The magnetic quantum number, ml, specifies the orientation and number of orbitals of electrons in a subshell. The value of the magnetic quantum number is dependent on the angular momentum quantum number I with values ranging from -I to +I.

The shape of the electron's orbital is determined by the angular momentum quantum number.

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Lorico [155]

Answer: $r_2=11.81 cm$

Explanation:

Given

$m_1=2.2\times 10^{-8} kg$

$m_2=4.8\times 10^{-8} kg$

same charge on both masses

potential Energy due to Magnetic Field =Kinetic Energy of Particle

$qV=\frac{mv^2}{2}$

$v=\sqrt{\frac{2qV}{m}}$

and we know

Force due to magnetic field will Provide centripetal Force

$qvB=\frac{mv^2}{r}$

$B=\frac{\sqrt{\frac{2Vm}{q}}}{r}$

and B is equal for both particles

thus $\frac{m}{r^2}=constant$

$\frac{m_1}{r_1^2}=\frac{m_2}{r_2^2}$

$r_2^2=\frac{4.8}{2.2}\times 8^2$

$r_2=11.81 cm$

4 0

3 years ago

Wanda has a cube of sugar. She crushes it into a powder. What has changed about the sugar?

stira [4]

Mass always stays the same therefore it can’t be c and d. Volume stays the same because she is not removing anything. Therefore it is a

5 0

3 years ago

Read 2 more answers

The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, w

jek_recluse [69]

Answer:

$XY=636N$

Explanation:

From the question we are told that:

Distance $d=0.35m$

Angle $\theta=32\textdegree$

Force $F=750N$

Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by

$XY=Fcos\theta$

$XY=750cos 32\textdegree$

$XY=636N$

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3 years ago

Atomic nuclei are made of protons and neutrons. This fact by itself shows thatthere must be some other type of force in addition

Stells [14]

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It is actually strong force which holds proton together. At this short distance, strong force comes into play and is several times stronger than the repulsive force.

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4 years ago

A pendulum is transported from sea-level, where the acceleration due to gravity g is 9.80 m/s2, to the bottom of Death Valley. A

tatyana61 [14]

Answer: the value of g in Death Valley is 10.417 m/s²

Explanation:

Given that;

acceleration due to gravity at the point is g = 9.8 m/s²

Lets say the acceleration due to gravity at the bottom of Death valley is g'

as the period of the pendulum is decreased by 3.00%

T' = 0.97 T

T is the period of the pendulum at sea level and T' is the period of the pendulum at bottom of Death valley

therefore from the relation

T = 2π√(l/g)

g'/g = T²/T'²

g' = (T²/ (0.97T)²)g

g' = 1.063g

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therefore the value of g in Death Valley is 10.417 m/s²

7 0

3 years ago