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frez [133]
3 years ago
8

What acceleration will result when a 12 N net force applied to a 3 kg object?​

Physics
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

4m/s

Explanation:

due to newtons second law of motion

the accelerations that result when a 12-N net force is applied to a 3-kg object. A 3-kg object experiences an acceleration of 4 m/s/s.

HOPE THIS HELPS PLEASE MARK AS BRAINLIEST:)

Alla [95]3 years ago
8 0

Answer:

4m/s^2

Explanation:

Force = mass x acceleration

F = m x a

Given

Force F = 12N and

Mass m = 3kg

Therefore,

12 = 3 x a

Divide both sides by 3

12/3 = 3/3 x a

4 = a

a = 4m/s^2

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The velocity and acceleration of the skydiver will increase as she falls to the ground. According to Newton’s Law of gravity.
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How much heat is required to raise the temperature of 0.25 kg of water from 20°C to 30°C
pentagon [3]

Answer:

10500 J/kg/*C

Explanation:

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Nesterboy [21]

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125÷2= 62.5 is your average speed. If the train was resting it's not moving your going nowhere . If the train is traveling at constant speed in a straight line it's speed will increase going through mountains will slow it down. if the train is coming to a braking force its speed will decrease

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2 years ago
A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of
Elan Coil [88]

Given :

A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.

To Find :

The embankment in the height.

Solution :

Since no external force is acting in the system, therefore total energy will be conserved.

Initial kinetic energy of the object = Energy stored in spring

K.E _i = \dfrac{kx^2}{2}\\\\K.E_i = \dfrac{1730\times 0.136^2}{2}\\\\K.E_i = 16\ J

Also, initial potential energy is 0.

Now,

K.E_i + P.E_i = K.E_f + P.E_f\\\\16 + 0 = \dfrac{1.72\times 2.45^2}{2}+ mgh\\\\mgh =16 - 5.16\\\\h = \dfrac{16 - 5.16}{1.72 \times 9.8}\\\\h = 0.64\ m

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3 0
3 years ago
Two cylindrical resistors are made from same material and have the same length. When connected across the same battery, one diss
Ilia_Sergeevich [38]

Answer:

\frac{d_2}{d_1} = \sqrt2 = 1.41

Explanation:

As resistor is connected to the battery of constant EMF then the power across the resistor is given as

P = \frac{E^2}{R}

now if two resistors are made up of same material and of same length then due to different cross sectional area they both have different resistance

Due to different resistance they both will have different power

Since power is inversely depends on the resistance

So if the power is twice that of the other then the resistance must be half

so we have

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R_2 = \rho\frac{L}{A_2}

since one resistance is half that of other resistance

So the area of one must be twice that of other

so we have

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d_2 = 1.41 d_1

8 0
3 years ago
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