Question

A shopper in a supermarket pushes a loaded cart with a horizontal force of 11 N. The cart has a mass of 35 kg. The acceleration of gravity is 9.8 m/s 2 . Disregarding friction, how far will the cart move in 3.5 s, starting from rest? Answer in units of m.

Answer 1

Answer:

s = 1.925 meters

Explanation:

Given that,

Horizontal force acting on the cart, F = 11 N

Mass of the cart, m = 35 kg

To find,

Distance covered by the cart in 3.5 seconds if it starts from rest.

Solution,

As the cart is starting from rest, u = 0

Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

Since, $a=\dfrac{F}{m}$

$s=\dfrac{1}{2}\times \dfrac{F}{m}\times t^2$

$s=\dfrac{1}{2}\times \dfrac{11}{35}\times (3.5)^2$

s = 1.925 meters

Therefore, the distance covered by the cart is 1.925 meters.