Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
5:3. Simply by the common factor which is 6. 30 divided by 6 is five. 18 divided by 6 is 3. Therefore the simplest form is 5:3
44.
The closer it gets to -19, the closer the number goes to 44. It never hits it exactly though, but based off the trend (43.95, 43.995, 43.9995) we can tell that it gets closer to 44 each time.
Hope this helps! (:
Use a proportion.
121/16.5 = 22/m
121m = 16.5 * 22
11m = 16.5 * 2
11m = 33
m = 3
3 minutes.