Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
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Answer:
$268.80
Step-by-step explanation:
You multiply 336 by 0.2 as it give what the 20% is, which is 67.2. You then subtract 336 by 67.2 and get the value from last year.
I will have $2721 at the beginning of the eighth year.
The beginning of the eighth year is the end of <em>seven years of investing</em>.
The formula for the future value (FV) of my investment is
FV = <em>C</em>(1 + <em>r</em>)^<em>n</em>
where <em>C</em> = my initial cash
<em>r</em> = the interest rate
<em>n</em> = the number of years
FV = $2000(1.045)^7 = $2722
To make 90 tortillas, he needs to make 6 batches. 6*15=90
2 cups masa per batch ->. 2 * 6=12 cups Masa
1.5 water per batch -> 1.5. * 6= 9 cups water
This is much easier to explain with a picture so...
First, simplify the coefficients. Then, simplify the variables. The y's cancel each other out so, you have your answer of -3x
