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Degger [83]
3 years ago
8

Find the orthocenter for the triangle described by each set of vertices.

Mathematics
1 answer:
givi [52]3 years ago
4 0

Answer:

The orthocentre of the given vertices ( 2 , -3.5)

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

The orthocentre is the intersecting point for all the altitudes of the triangle.

The point where the altitudes of a triangle meet is known as the orthocentre.

Given Points are K (3.-3), L (2,1), M (4,-3)

<em>The Altitudes are perpendicular line from one side of the triangle to the opposite vertex</em>

<em>The altitudes are  MN , KO , LP</em>

<u><em>step(ii):-</em></u>

<em>  </em>  Slope of the line  

                          KL = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } = \frac{1-(-3)}{2-3} = -4

The slope of MN =

The perpendicular slope of KL

                           = \frac{-1}{m} = \frac{-1}{-4} = \frac{1}{4}

The equation of the altitude

                                 y - y_{1} = m( x-x_{1} )

                                y - (-3) = \frac{1}{4} ( x-4 )

                               4y +12 = x -4

                                x - 4 y -16 = 0 ...(i)

Step(iii):-

 Slope of the line  

                          LM = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } = \frac{-3-1}{4-2} = -2

The slope of KO =

The perpendicular slope of LM

                           = \frac{-1}{m} = \frac{-1}{-2} = \frac{1}{2}

The equation of the altitude

                                 y - y_{1} = m( x-x_{1} )

The equation of the line passing through the point K ( 3,-3) and slope

m = 1/2

                                y - (-3) = \frac{1}{2} ( x-3 )

                                2y +6 = x -3

                             x - 2y -9 =0 ....(ii)    

Solving equation (i) and (ii) , we get

  subtracting equation (i) and (ii) , we get

                   x - 4y -16 -( x-2y-9) =0

                       - 2y -7 =0

                      -2y = 7

                        y = - 3.5

Substitute y = -3.5 in equation x -4y-16=0

               x - 4( -3.5) - 16 =0

               x +14-16 =0

                x -2 =0

                  x = 2

The orthocentre of the given vertices ( 2 , -3.5)

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Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

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Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

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Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

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Answer:

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10,560:2 ; 2 miles in 2 hours is 5,280+5,280 (10,560) feet in 2 hours

3 ft = 1 yd ; every 3 feet is a yard, so divide 10,560 by 3

10,560/3 = 3520 yds ; Jorge can walk 3,520 yds in 2 hours

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The conditional relative frequency table was generated using data that compares the favorite subjects of male and female student
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Answer: Using the information of the conditional relative frequency table, 123 students in the survey said that math was their favorite subject.


Solution:

1. The survey was given to 120 male students.

Acconding with the table, the proportion of male students with Math as favorite subject is 0.35. The quantity of male students with Math as favorite subject would be:

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2. The survey was given to 180 female students.

Acconding with the table, the proportion of female students with Math as favorite subject is 0.45. The quantity of female students with Math as favorite subject would be:

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Then the total of students in the survey said that math was their favorite subject would be:

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3 years ago
Read 2 more answers
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