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dusya [7]
3 years ago
8

The graph of function g is a parabola with the vertex located at (5,9). The parabola also passes through the point (3, 1). Which

of the following is an
equation in vertex form for this function?
Mathematics
1 answer:
lara [203]3 years ago
4 0

I just did this the answer is C. g(x) = –2(x – 5)2 + 9

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If x= yand y = Z, which statement must be true?
umka21 [38]

Answer:

The answer is

B. x =>z

They all equal the same.

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4 years ago
(6+3)+21=6+(3+21) name each property of addition or multiplication
Anna007 [38]
(6 + 3) + 21 = 6 + (3 + 21)

It's an ASSOCIATIVE PROPERTY
(a + b) + c = a + (b + c)
7 0
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Solve y=x^2+23 for x
LenKa [72]

For this case we must clear x from the given equation:

y = x ^ 2 + 23

We passed 23 subtracting the other side of equality:

y-23 = x ^ 2

By definition, a ^ 2 = bis written as a = +/-\sqrt{b}

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7 0
3 years ago
Identify the radius and center.<br><br> x^2 + y^2 - 2x + 4y - 11 = 0
miss Akunina [59]
<h2>Hello!</h2>

The answer is:

Center: (1,-2)

Radius: 4 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where,

"h" and "k"are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^2+y^2-2x+4y-11=0

So, solving we have:

x^2+y^2-2x+4y=11

(x^2-2x+(\frac{2}{2})^{2} )+(y^2+4y+(\frac{4}{2})^{2})=11+(\frac{2}{2})^{2} +(\frac{4}{2})^{2}\\\\(x^2-2x+1)+(y^2+4y+4)=11+1+4\\\\(x^2-1)+(y^2+2)=16

(x^2-1)+(y^2-(-2))=16

Now, we have that:

h=1\\k=-2\\r=\sqrt{16}=4

So,

Center: (1,-2)

Radius: 4 units.

Have a nice day!

Note: I have attached a picture for better understanding.

5 0
4 years ago
A complex fraction is a fraction of a fraction.<br><br> A.True<br> B.False
andrew11 [14]
A complex fraction is a fraction of a fraction
7 0
3 years ago
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