Answer:
3/2y-3/8z
Step-by-step explanation:
-3/8(-4y)-3/8z
Part A : Substitution
Elimination
Argumentated matrices.
Part B :
1. Substitution is a method of solving systems of equations by removing all but one of the variables in one of the equations and then solving that equation. This is achieved by isolating the other variable in an equation and then substituting values for these variables in other another equation.
2. Elimination is another way to solve systems of equations by rewriting one of the equations in terms of only one variable. The elimination method achieves this by adding or subtracting equations from each other in order to cancel out one of the variables.
3. Augmented matrices can also be used to solve systems of equations. The augmented matrix consists of rows for each equation, columns for each variable, and an augmented column that contains the constant term on the other side of the equation.
Part C :
7x +y = 14
5x + y = 4
X= 5 and y = - 21
Hope this Helps : )
<span>6 + 2x = 24
2x = 18
x = 9
answer
9
----------
</span><span>3x – 5 ≥ 7
3x </span>≥ 12
x ≥ 4
answer
<span>{4, 5, 6}
</span>
--------------
<span>4x – 3 ≥ 5
</span><span>4x ≥ 8
</span><span>x ≥ 2
answer
</span><span>{2, 3, 4}
</span>
-----------------
<span>3r ≤ 4r – 6
r </span> ≥ 6
answer
<span>{6, 7, 8, 9,10}</span>
Answer:
Part 1) The exact solutions are
and
Part 2) (1.79, 8.58)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
When solving the system of equations by graphing, the solution of the system is the intersection points both graphs
<em>Find the exact solutions of the system</em>
equate equation A and equation B

The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula
so
The solutions are
<em>Find the values of y</em>
<em>First solution</em>
For 


The first solution is the point
<em>Second solution</em>
For 


The second solution is the point
Round to the nearest hundredth
<em>First solution </em>
-----> 
-----> 
see the attached figure to better understand the problem
Answer:
<h2>(f · g)(x) is odd</h2><h2>(g · g)(x) is even</h2>
Step-by-step explanation:
If f(x) is even, then f(-x) = f(x).
If g(x) is odd, then g(-x) = -g(x).
(f · g)(x) = f(x) · g(x)
Check:
(f · g)(-x) = f(-x) · g(-x) = f(x) · [-g(x)] = -[f(x) · g(x)] = -(f · g)(x)
(f · g)(-x) = -(f · g)(x) - odd
(g · g)(x) = g(x) · g(x)
Check:
(g · g)(-x) = g(-x) · g(-x) = [-g(x)] · [-g(x)] = g(x) · g(x) = (g · g)(x)
(g · g)(-x) = (g · g)(x) - even