Answer:
a.
9.88
Explanation:
ΔG = - 2.303 RT log Ka
ΔG is change in free energy at temperature T , Ka is equilibrium constant
- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa
- log Ka = 9.88 .
pKa = 9.88 .
Answer:
to understand the human life
Explanation:
hope this helps :)
Answer:
12.7551
Explanation:
The given chemical equation follows:
The equilibrium constant for the above equation is 0.28.
We need to calculate the equilibrium constant for the reverse equation of above chemical equation, which is:
The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.
If the equation is multiplied by a factor of '2', the equilibrium constant of the reverse reaction will be the square of the equilibrium constant of initial reaction.
The value of equilibrium constant for reverse reaction is:
<u>Hence, the value of equilibrium constant for reverse reaction is 12.7551.</u>
will be largest for
.
Explanation: Ionization energy is the energy to knock off an electron from a gaseous atom of ion. First ionization energy or
is the energy required to remove 1 loosely held electron from 1 mole of gaseous atoms to produce 1 mole of gaseous ion carrying (+)1 charge.

The electrons are filled according to Aufbau's rule and the orbitals which are strongly held to the nucleus follows the order
.
Electron is released from the outermost shell that is from the electrons which are loosely held to the nucleus, this follows the pattern
.
In configurations,
The loosely held orbital is 4s, therefore electron will be lost from that easily.
Now, in 3p orbital, one configuration has 5 electrons and one has 1 electron.
The configuration having 5 electrons will be more tightly held by the nucleus because it has more electrons that the one having only 1 electron. Hence, the electron will be lost easily from the configuration having
as the valence shell.
Therefore, the configuration
will the largest
.