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3 years ago

What is 1+1 guys . . . . . . . . .

Mathematics

2 answers:

Lady bird [3.3K]3 years ago

4 0

Answer: Well according to my careful calculations...... it's 3

Step-by-step explanation:

zaharov [31]3 years ago

3 0

Answer:

Step-by-step explanation:

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Find the number of distinct triangles with the measurements a = 8, b = 14, and A = 30°.

Maslowich

Answer: 2

Step-by-step explanation:

By the law of sines,

$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \frac{\sin B}{14}=\frac{\sin 30^{\circ}}{8} \\ \\ \frac{\sin B}{14}=\frac{1}{16} \\ \\ \sin B=\frac{14}{16} \\ \\ B=\sin^{-1} \left(\frac{14}{16} \right), 180^{\circ}-\sin^{-1} \left(\frac{14}{16} \right) \\ \\ B \approx 61.04^{\circ}, 118.96^{\circ}$

Since either of these values for B will form a triangle (as A+B will be less than 180 degrees), 2 triangles can be formed with these measurements.

5 0

2 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

3 years ago

What is 2x-{2-[2(x-2)-(2-x)]}=0

Ludmilka [50]

$2x-(2-(2(x-2)-(2-x)))=0\\
2x-(2-(2x-4-2+x))=0\\
2x-(2-(3x-6))=0\\2x-(2-3x+6)=0\\
2x-(-3x+8)=0\\
2x+3x-8=0\\
5x=8\\
x=\dfrac{8}{5}$

3 0

3 years ago

Your family buys tickets for the Ranger game. Each ticket costs $16. You also have to pay for parking. After buying 4 tickets, y

Yuliya22 [10]

Part (a)

Answer: $32.50

--------------------

Work Shown:

Each ticket costs $16. If you buy four of them, then you paid 4*16 = 64 dollars.

The total bill was $96.50

This leaves 96.50-64 = 32.50 for parking.

======================================================

Part (b)

Answer: y = 16x+32.50

--------------------

Work Shown:

x = number of tickets

y = total bill (in dollars)

1 ticket costs 16 dollars

x tickets cost 16x dollars since we multiply both values by x

Add on the cost of parking to get a total bill of y = 16x+32.50

======================================================

Part (c)

Answer: at most 13 tickets

In other words, 13 is the max you can get.

--------------------

Work Shown:

Plug y = 250 into the equation found back in part (b). Solve for x

We'll follow PEMDAS in reverse to isolate x

y = 16x+32.50

250 = 16x+32.50

16x+32.50 = 250

16x = 250-32.50

16x = 217.5

x = 217.5/16

x = 13.59375

Since we can't buy a fraction of a ticket, we must round down to the nearest whole number. We cannot round to x = 14 despite the value 13.59375 being closer to 14 as it is to 13.

x = 13 is the answer we're after.

If we plug in x = 13, we get

y = 16x+32.50 = 16*13+32.50 = 240.5

while x = 14 leads to

y = 16x+32.50 = 16*14+32.50 = 256.5

The first result of $240.50 is under $250 while the second result $256.50 is over $250. So that's why x = 13 is the largest number of tickets we can buy.

6 0

3 years ago

Please answer correctly !!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!

quester [9]

9514 1404 393

Answer:

see below

Step-by-step explanation:

The image you posted does not let us "click and drag." The angle bisector you create will cut the given 74° angle into two (equal) 37° angles. Your final image may look something like this:

8 0

3 years ago