Answer:
1.28 M
Explanation:
Step 1: Given data
Mass of luminol (solute): 17.0 g
Volume of water: 75.0 mL (this is also the volume of solution)
Step 2: Calculate the moles corresponding to 17.0 g of luminol
The molar mass of luminol is 177.16 g/mol.
17.0 g × 1 mol/177.16 g = 0.0960 mol
Step 3: Calculate the molarity of the solution
We will use the definition of molarity
M = moles of solute / liters of solution
M = 0.0960 mol / 0.0750 L = 1.28 M
Answer:
Explanation:
Before writing this equation in a molecular equation form, let's identify each species:
- phosphorus is a non-metal represented by 'P', it is solid at standard conditions;
- iron(III) oxide is an ionic compound consisting of iron(III) cations with a 3+ charge, as well as of oxide anions with a 2- charge, this means we may represent it as , which is also a solid material at standard conditions;
- tetraphosphorus decoxide consists of 4 phosphorus atoms and 10 oxygen atoms, as stated by the prefixes, this is also a solid;
- iron metal is simply 'Fe'.
Putting all of this into a single equation and balancing it, we obtain:
<span>1.006 g of Na2CO3 is left; which means that (2.714 -1.006) g of water are lost from the hydrated sodium carbonate
So, water present = </span>(2.714 -1.006) = 1.708 g.
Molecular Wt. of water is =18 g
so moles = 1.708/18 moles = 0.095 moles.
Now, <span>Na2CO3 has molecular wt. of = 23x2 + 12 +3x16 = 106 g,
so moles of Na2CO3 = 1.006/106 moles = 0.0095 moles </span>
<span>Ratio is = 0.0095 / 0.095 = 1 / 10 [ moles of Na2CO3 / moles of H2O ]
Ratio is saying on every 1 mole of Na2CO3 , there are 10 moles of H2O
so x is 10</span>
Answer:
#2, 4, & 5
Explanation:
In number 1 there are unequal Cu's
In number 3 there are unequal Cl's
It’s true you can fide it on quizzes .