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Natalka [10]
3 years ago
8

The mean of the numbers 15,21,17,26,18 and 29 is 21. Calculate the standard deviation. ​

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

4.62910049578

Step-by-step explanation:

variation is standard deviation squared

variance = 21.428571428571

square root variance for answer.

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michael found a job listed in the classified ads that pays a yearly salary of $57.3k what is the weekly salary based on this ann
Zepler [3.9K]
Since there are 52 weeks in a year, we have 52 weeks=1 year and 
57.3*1000 (k means 1,000) = 573,000/1 year. Multiplying it by 1 year/52 weeks (to cancel the years), we get 573000/52=around $<span>11019.23 as our answer</span>
8 0
3 years ago
A school debate team has 4 girls and 6 boys. A total of 3 of the team members will be chosen to participate in the district deba
mariarad [96]
There are 4+6=10 people in the team.
First calculate in how many ways you can choose 3 people from a group of 10 people, using combination:
(^{10} _3)=\frac{10!}{3!(10-3)!}=\frac{10!}{3! \times 7!}=\frac{7! \times 8 \times 9 \times 10}{6 \times 7!}=\frac{8 \times 9 \times 10}{6}=\frac{720}{6}=120
You can choose 3 people in 120 ways.

You can select 1 girl from a group of 4 girls in 4 ways.
Calculate in how many ways you can choose 2 boys from a group of 6 boys:
(^6 _2)=\frac{6!}{2! (6-2)!}=\frac{6!}{2! \times 4!}=\frac{4! \times 5 \times 6}{2 \times 4!}=\frac{5 \times 6}{2}=\frac{30}{2}=15
You can choose 2 boys in 15 ways.
Using the rule of product, you can calculate that you can choose 1 girl and 2 boys in 4×15=60 ways.

The probability of choosing 1 girl and 2 boys is the number of ways you can choose 1 girl and 2 boys divided by the number of ways you can choose 3 people from the group.
 P=\frac{60}{120}=\frac{1}{2}=50\%

The probability is 1/2, or 50%.
4 0
3 years ago
Select the correct answer.
erastovalidia [21]

Answer:

here

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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Sati [7]
Perpendicular: slope is -3/2

Based on this I would already know the answer is A.
3 0
3 years ago
In an isosceles triangle two sides are equal. The third side is two less than twice the length of the two equal sides. The perim
pogonyaev

Answer:

The equal sides' length = 10

Third side length = 18

Step-by-step explanation:

Let the two equal sides' length be "x"

Let the third side length be "y"

Third side (y) is 2 LESS THAN TWICE the equal side, so we can write:

y = 2x - 2

The perimeter is 38. The perimeters is the sum of all three sides. So we can write:

x + x + y = 38

Replacing y with 2nd equation, we have:

x + x + (2x - 2) = 38

Now, we can solve this for x first:

x + x + (2x - 2) = 38\\x+x+2x-2=38\\4x=38+2\\4x=40\\x=10

Now, y is:

y = 2x - 2

y = 2(10) - 2

y = 20 - 2

y = 18

The equal sides' length = 10

Third side length = 18

3 0
3 years ago
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