Question

There is some gas in a container at pressure 136 atm. When 142 dm3 gas is released at pressure of 1 atm,then the pressure of the vessel is 131.6 atm. What is the volume of the Tank?

Answer 1

Answer:

228.7$dm^{3}$

Explanation:

According to Boyle's law

P1V1 = P2V2

where P1& P2 are initial and final pressure

and V1& V2 and initial and final volumes respectively.

Given:

P1 = 136atm, P2 = 131.6atm

V1 = 142$dm^{3}$; V2 = ?

V2 = $\frac{P1V1}{P2}$ = $\frac{136*142}{131.6}$

= 146.7$dm^{3}$

Total volume, V = V1 + V2

=146.7 + 142

= 228.7$dm^{3}$