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Sergeu [11.5K]
3 years ago
9

There is some gas in a container at pressure 136 atm. When 142 dm3 gas is released at pressure of 1 atm,then the pressure of the

vessel is 131.6 atm. What is the volume of the Tank?
Chemistry
1 answer:
mamaluj [8]3 years ago
8 0

Answer:

228.7dm^{3}

Explanation:

According to Boyle's law

P1V1 = P2V2

where P1& P2 are initial and final pressure

and V1& V2 and initial and final volumes respectively.

Given:

P1 = 136atm, P2 = 131.6atm

V1 = 142dm^{3}; V2 = ?

V2 = \frac{P1V1}{P2} = \frac{136*142}{131.6}

= 146.7dm^{3}

Total volume, V = V1 + V2

=146.7 + 142

<u>= 228.7</u>dm^{3}<u></u>

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Lithium, sodium and potassium are all in group 1 of the periodic table. Which of these has the lowest boiling point?
kvv77 [185]

Answer:

Potassium

Explanation:

In group one of the periodic table both the melting and the boiling points usually decrease down the group.

Now, down the group, it's lithium that comes first, then sodium, then potassium.

Thus, among the 3, potassium is furthermost down the group by virtue of the factor it has the highest atomic number.

Therefore, we can say that potassium has the lowest boiling point among the 3.

5 0
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Consider the following equilibrium systems: A⇌2B ΔH o =20.0 kJ/mol Reaction 1 A+B⇌C ΔH o =−5.4 kJ/mol Reaction 2 A⇌B ΔH o =0.0 k
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Answer:

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Let us consider the following reactions:

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Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol

Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol

To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>

Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.

Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.

Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.

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Explanation:

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As the charge of all electrons are equal, the repulsive force exerted by each of them is also going to be equal. So, as K has more electrons repulsing its valence electron than Na, it has greater electron shielding.

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