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3 years ago

HALPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

2 answers:

vova2212 [387]3 years ago

7 0

Answer:

False

Step-by-step explanation:

Maurinko [17]3 years ago

4 0

Answer:

False

Step-by-step explanation:

The first one 4-(-20) the negative/subtractive signs cancel each other out so the question is really just 4+20 which is 24.

The second one 4+(-20) is obviously different and the answer is -16.

I hope this helps, and have a great day!

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A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Is this true? And also how does the equation from y-3=3(x-4) become a positive y+3=3x-12?

EastWind [94]

Step-by-step explanation:

the right equation is :

y-y1=m(x-x1)

y+3=3(x+4)

y+3= 3x+12

y=3x+12-3

y=3x+9

7 0

3 years ago

If it takes 5 workers 4 hours to build a 10 foot wall, and the number of hours is directly proportional to the number of walls t

pychu [463]

4x10=40 10x10=100 ft/10 100/10=10 walls

4 0

3 years ago

D₁ vide using x² - 2x² 2× +3× -5 by ×-3 using synthetic division.

Vaselesa [24]

Answer:

Step-by-step explanation:

I think you are trying to use synthetic division for

$x^{4} -2x^{3} -2x^{2} +3x-5$ divided by x-3

First

x -3 = 0 , make it equal to 0 and add 3 to both sides

x = 3

Then we write all the coefficients and continue with

a pattern of multiply by 3 and add to the next coefficient.

See attachment.

5 0

1 year ago

PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!! QUESTION ATTACHED

DIA [1.3K]

Angle-5 and angle-7 are 'vertical angles', so they're equal,
and we can write ...
 10x- 9 = 9x

Subtract 9x from each side: x - 9 = 0

Add 9 to each side: x = 9

Now that we know what 'x' is, we can find the size of Angles-5 and -7 .

Angle-7 = 9x = 81° .

Now look at Angle-6 ... the one that's the answer to the problem.

Angle-6 and -7 together make a straight line, so they must
add up to 180°.

 Angle-6 + 81° = 180°

Subtract 81° from each side: Angle-6 = 99° .

4 0

3 years ago