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3 years ago

Y= 6x + 5 is the equation of a straight line graph. what is its gradient?

Mathematics

1 answer:

aleksley [76]3 years ago

5 0

The gradient is 6
y=mx+b
where m= gradient
b=y intercept

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Please help with the main graph that has the 3 bullet points!!

Ierofanga [76]

Answer:

Identify the correct parent function.

$f(x)=x^{2}$

Is the relation also a function?

Yes, all inputs have one output.

Is it continuous or discrete?

Continuous, it has a solid line.

What is $f(2)$ ?

$f(2)=4$

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3 years ago

Question 2 of 10

Setler [38]

Answer:

D. 95 + 47 + 5.12 12 ÷ 4 ≠ 4 ÷ 12.

Step-by-step explanation:

(70 +30) + 72 B. 21 + (-14) + (-53) O C. 67 +1 - 18. So 12÷4≠4÷1/4 + 3/4 + 2. C. 20 + 80 + (-11)

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3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a

kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, $s=\frac{dx}{dt}=470\ mi/h$

Now, applying Pythagoras theorem to the triangle, we have:

$D^2=h^2+x^2\\\\D^2=1+x^2$

Differentiating with respect to time 't', we get:

$2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)$

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

$2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi$

Now, plug in all the given values and solve for $\frac{dD}{dt}$ . This gives,

$\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h$

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

6 0

3 years ago

Last week would wilbur ran 25miles less than aliyah. wilbur ran 18 miles. how many miles did aliyah run

andreyandreev [35.5K]

The correct answer is 43

4 0

3 years ago

What is the length of DE

HACTEHA [7]

Answer:

DE = 20units

Step-by-step explanation:

In Δ ABC,

angle A is congruent to angle B.... (given)

therefore, ΔABC is an isoceles triangle.

therefore, CA = CB..... (side opposite to congruent angles are congruent in an isoceles triangle)

therefore, CB = 4 units

In ΔCDE,

angle D is congruent to angle E.... (given)

therefore, ΔCDE is an isoceles triangle.

therefore, CD = CE

therefore, CD = 8 units

ΔCDE ~ ΔCBA

therefore,

$\frac{cd}{cb} = \frac{ce}{ca} = \frac{de}{ab} \\ therefore \: \frac{8}{4} = \frac{8}{4} = \frac{de}{10 } \\ therefore \\ \frac{2}{1 } = \frac{de}{10 } \\ de \: = 2 \times 10 = 20units$

8 0

3 years ago