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myrzilka [38]
2 years ago
9

WHERES THE BEEF??????????????????? hehehe sorry ab that im just HELLA bored over here ;)

Mathematics
1 answer:
ddd [48]2 years ago
5 0
Me too tbhh school sucks omggg I have to put like an equation because If
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Sean determines that the triangle shown in the diagram has angle measures of 40°, 40°, and 100°. Is Sean correct?
kotykmax [81]
The bottom left angle is 180 -80=(100)

So the remaining 2 angles are equal 80
As all angles in a triangle are equal to 180

X+5 + x - 5 =80
Simplify
2x=80
X=40

Soo one of the angles are 40-5 which is (35)
And the other is 40+5 which is (45)
So sean is not correct
~sorry sean teehee
6 0
3 years ago
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Which expression is equivalent to b^m x b^n? A. b^m+n B. b^m-n C. b^mx n D. b^m/n
noname [10]
The formula for multiplying exponents are such below.

(b^m)^n = b^mn
b^m/b^n=b^(m-n)
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4 0
3 years ago
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How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

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3 years ago
WILL GIVE 20 BRANLY- Find the value
Alika [10]

Answer:

Find the value of what? Update the question and I will answer

Step-by-step explanation:

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3 years ago
How do I find a unit rate of 17.86
Reil [10]
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