To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"
Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.
Now, we have to recall that:
- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles
- also the sum of all the angles in any triangle is 180 degrees
Now, considering the isosceles triangle OQR, we have that:
Now, since the figure already shows that angle 
Now, since we have established that the base angles 
we can now solve the above equation for m<2 as follows:
Therefore, the correct answer is: option D
Answer:
-b/2a is the equation to find the x coordinate of the vertex point and it's y, when x is plugged into the quadratic equation.
Step-by-step explanation:
Answer:
1. 7.1 cm
2. 10.9 cm
Step-by-step explanation:
1. You know the legs of a right triangle must be shorter than the hypotenuse. The only answer choice shorter than 8 cm is 7.1 cm.
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2. By the Law of Sines, ...
AB/AC = sin(ACB)/sin(B)
AB = AC·sin(72°)/sin(38°) = 1.545·AC
The approximate value of AC from problem 1 is sufficient to get you close to the answer.
AB ≈ 7.1×1.545 ≈ 10.9 . . . cm
Since it is f of g you have to start by plugging in g(x) into f(x)
(4-3x)^2-3
Then just solve the equation
(4-3x)^2-3
(4-3x)(4-3x)-3 Square the binomial
8-12x-12x+9x^2-3 Combine like terms
5-24x+9x^2 Final answer
