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andrew11 [14]
3 years ago
13

Which of the the following quantities has the same unit as kilowatt - hour?

Physics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

I think (d) is your answer...

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What is the simplest relationship between the angular wavenumber k and just one of the other kinematic variables?
Inessa [10]

Answer : k=\dfrac{\omega}{k}

Explanation :

The word kinematics means the study of motion. Kinematic variables gives the description of the motion of the body.

Displacement, Velocity, acceleration and time are associated with the motion of particle.

Wavenumber is defined as the frequency of wave, which is measured in cycles per unit distance.

Wave number is also defines as:

k=\dfrac{2\pi}{\lambda}

where, \lambda is wavelength

k=\dfrac{2\pi}{\lambda}\times \dfrac{T}{T}

since, \dfrac{2\pi}{T}=\omega \ and\ \dfrac{1}{V}=\dfrac{T}{\lambda}

So, k=\dfrac{\omega}{V}

Where, \omega is angular frequency and V is velocity of wave.

Hence, the  relationship between the angular wavenumber k and and kinamatic variable V is

k=\dfrac{\omega}{V}

6 0
4 years ago
Jose throws a ball at 92 mi/hr horizontally. If there were NO air resistance, how
Trava [24]

Answer:

It should be 92 mi/h

Explanation:

Because there is no air resistance there is nothing pushing against it to slow it down, so only the initial force and gravity are acting on the ball

7 0
4 years ago
Which option is an example of chemical energy being transformed into thermal energy?
mylen [45]

Answer:

d

Explanation:

3 0
3 years ago
Read 2 more answers
Могут ли быть сообщающиеся сосуды неодинаковы пр своей форме
Rudik [331]

Answer:

no

Explanation:

they cannot because they contain the same amount of liquid

8 0
4 years ago
Read 2 more answers
A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele
Lunna [17]

Answer:

Part a)

W = 0.15 J

Part b)

W = 0.11 J

Part c)

U = 0.19 J

Part d)

U = 0.038 J

Part e)

U = 0.075 J

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

W = mg(5R - R)

W = 0.032(9.8)(4)(0.12)

W = 0.15 J

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

W = mg(5R - 2R)

W = 3mgR

W = 0.11 J

Part c)

Potential energy at P point is given as

U = mgH

U = 0.032(9.8)(5)(0.12)

U = 0.19 J

Part d)

Potential energy at Q point is given as

U = mgH

U = 0.032(9.8)(0.12)

U = 0.038 J

Part e)

Potential energy at top point is given as

U = mgH

U = 0.032(9.8)(2)(0.12)

U = 0.075 J

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

8 0
4 years ago
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