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3 years ago

9

How is the setting in chapter one significant to a possible theme in chapter one of mice and men?

1 answer:

ra1l [238]3 years ago

4 0

In Steinbecks of nice and men, the setting at the start of chapter one is “ a few miles south of Soledad” Lenny and George have been walking for what seems like four miles. George is aggravated having been dropped if by a truck driver who said they didn’t have far to go

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If an earthquake occurred in Miami, Florida, then how long would it take for a seismic station in Seattle, Washington, to pick u

Juliette [100K]

0.017s

Explanation:

Given parameter

Distance = 5000km = 5 x 10⁶m

Unknown:

time taken = ?

Solution:

We use the normal speed equation to solve this problem as we take the speed of the wave to be 3 x 10⁸m/s.

Speed = $\frac{Distance }{Time taken}$

Inputting the parameters:

Time taken = $\frac{distance }{velocity of the wave}$

Time taken = $\frac{ 5 000000}{3 00000000}$ = 0.017s

Learn more:

Earthquake brainly.com/question/11292835

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2 years ago

Please help me with this i dont know it

Inessa05 [86]

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

5 0

2 years ago

Consider four point charges arranged in a square with sides of length L. Three of the point charges have charge q and one of the

nydimaria [60]

Answer: $F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]$

Explanation:

Given

Three charges of magnitude q is placed at three corners and fourth charge is placed at last corner with -q charge

Force due to the charge placed at diagonally opposite end on -q charge

$F_1=\frac{kq(-q)}{(L\sqrt{2})^2}$

where $L\sqrt{2}=$ Distance between the two charges

$F_1=-\frac{kq^2}{2L^2}$

negative sign indicates that it is an attraction force

Now remaining two charges will apply the same amount of force as they are equally spaced from -q charge

$F_2=\frac{kq(-q)}{(L)^2}$

The magnitude of force by both the charge is same but at an angle of $90^{\circ}$

thus combination of two forces at 2 and 3 will be

$F'=\sqrt{2}\frac{kq^2}{2L^2}$

Now it will add with force due to 1 charge

Thus net force will be

$F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]$

6 0

3 years ago

An earthquake’s epicenter is _____.

Evgen [1.6K]

The point in which it originates.

4 0

3 years ago

Read 2 more answers

Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.330. At what minimum rate wo

Helga [31]

Answer: $3.23 m/s^2$

Explanation:

Given

$\mu_s =0.330$

Frictional Force is balanced by force due to car acceleration

Frictional force $F_s$

$F_s=ma_{min}$

$\mu_sN=ma_{min}$

$\mu_s\cdot mg=ma_{min}$

$a_{min}=\mu_s \cdot g=0.330\times 9.8=3.23 m/s^2$

6 0

3 years ago