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Pie
4 years ago
9

How is the setting in chapter one significant to a possible theme in chapter one of mice and men?

Physics
1 answer:
ra1l [238]4 years ago
4 0
In Steinbecks of nice and men, the setting at the start of chapter one is “ a few miles south of Soledad” Lenny and George have been walking for what seems like four miles. George is aggravated having been dropped if by a truck driver who said they didn’t have far to go
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Consider two samples of gas. Sample A consists of n moles and is kept at temperature T in container of volume V. Gas B consists
MrRissso [65]

Answer: e. P/2

Explanation:

For ideal gases, we have the relation:

P*V = n*R*T

where:

n =  number of mols

R = Gas constant

T = temperature

V = volume

P = pressure.

We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:

Pa = (n*R*T)/V.

For sample B, we have:

n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:

Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)

and:

(n*R*T/V) = Pa

Then we can replace it and we get:

Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.

Then the correct option is e.

6 0
3 years ago
A man walks 30 m to the west, then 5 m to the east in 45 seconds. What is his average speed?
dsp73

The average speed is  0.55 m/s

<h3>What was his displacement?</h3>

Displacement is defined as the change in position of an object.

Mathematically,

D = Initial value - Final Value

D = 30 - 5 = 25m

Now , We have to find the average velocity,

Average velocity is calculated by the formula V = D/t,

where V equals the average velocity, D equals total displacement and t equals total time.

V = D/t

V = 25 m / 45s

V = 0.55 m/s

So , The average speed is o.55 m/s

learn more about average speed:brainly.com/question/9834403

#SPJ1

5 0
2 years ago
A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8 coulombs. What is the electric field at t
Alborosie
The electric field E of a charge is defined as E=F/Q where F is the Coulomb force and Q is the test charge. 

E=(1/Q)*k*(q*Q)/r², where k=9*10^9 N*m²/C², q is the point charge, Q is the test charge and r is the distance between the charges.

So E=(k*q)/r² 

When we input the numbers we get that electric field E of a point chage q is:

E=(9*10^9)*(5.4*10^-8)/0.2²=486/0.04=12150 N/C.
This is roughly E=12000 N/C =1.2*10^4 N/C
The correct answer is B. 
6 0
3 years ago
Read 2 more answers
The distance to the other planets in the Solar System from the Earth depends on where they are in their orbit. The closest that
Afina-wow [57]

Answer:

3.6 arcsec

Explanation:

 angular diameter = diameter / distance

diameter is constant

so angular diameter ∝ 1 / distance

angular diameter = k / distance

For first case ,

18 = k / .5

for second case let angular diameter be D .

D = k / 2.5

dividing ,

D / 18 = .5 / 2.5 = 1 / 5

D = 18 / 5 = 3.6 arcsec

3.6 arcsec is the answer .

3 0
3 years ago
If E = mc^2 then what does c = ?
scoundrel [369]
E = Energy m = Mass c = Speed of light.
4 0
3 years ago
Read 2 more answers
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