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Fynjy0 [20]
4 years ago
6

Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object

moves with constant acceleration. Which part of a velocity vs. time graph can be used to calculate the displacement of the object?
the area of the rectangle under the line
the area of the rectangle above the line
the area of the rectangle plus the area of the triangle under the line
the area of the rectangle plus the area of the triangle above the line
Physics
1 answer:
svlad2 [7]4 years ago
5 0

Answer:

The area of the rectangle plus the area of the triangle under the line

Explanation:

In this case, the object moves with constant acceleration. Initial speed of the object is 0.

Equation of kinematics :

v = u +at

v = at

v is directly proportional to time. If means that the graph is straight line passing through origin. We know that area under v-t graph gives displacement. So, the correct option is (c).

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While an object is moving at a constant 20 m/s, a 5 N forcepushes the object to the left. At the same time, a 5 N force ispushin
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Answer: 20m/s.

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Remember the second Newton's law:

F = a*m

This is:

The net force acting on an object is equal to the mass of the object times the acceleration of the object.

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We also have a force of 5N pushing the object to the left.

These forces act on opposite directions.

Then the net force will be equal to the difference of these forces, this is:

F = 5N - 5N = 0N

Then the net force is 0N, then we have:

0N = m*a

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This means that the acceleration of the object is 0, then the velocity of the object does not change.

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