Answer:
Oxidation - reduction reaction which is called redox reaction.
Explanation:
The type of reaction that is a part of another type but treated separately is called Oxidation - reduction reaction.
Thus is because they usually involve 2 separate half reactions which are oxidation reactions that involve loss of electrons and then reduction equations which involve gain of electrons.
They are treated separately for example when sodium reacts with chlorine to form sodium chloride.
2Na + Cl2 = 2NaCl
Now, sodium undergoes oxidation by loosing elctrons and it's half reaction is;
2Na → 2Na^(+) + 2e^(-)
Meanwhile chlorine undergoes reduction by gaining electrons and its half reaction is;
Cl2 + 2e^(-) → 2Cl^(-)
Answer:
The motion of the water molecules increase as heat is added.
Explanation:
Hello!
In this case, in general terms, one can know that molecules and heat have a relationship by which one affects the other, more specifically, the heat affects how the molecules behave. In such a way, as the heat added to a system increases its internal energy, one can notice that energy speeds up the molecules because they acquire such energy and the motion starts being increased, it means, the molecules start moving or vibrating faster than before of that heat addition. This is due to the increase of the internal energy, which based on the first law of thermodynamics is related with the velocity of the molecules.
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"Physical changes occur when objects or substances undergo a change that does notchange their chemical composition. This contrasts with the concept of chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances."
Answer:0.286M
Explanation:
10.7g / 149.89g/mol×0.25L
There are a number of
ways to express concentration of a solution. This includes molarity. Molarity
is expressed as the number of moles of solute per volume of the solution. The
concentration of the solution is calculated as follows:
<span> </span><span>Molarity = 15.5 g NaOH (1 mol NaOH / 40 g NaOH) / .250 L
solution</span>
<span>Molarity = 1.55 M</span>