1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
1 year ago
11

Sulfur dioxide emissions from coal-burning power plants are removed by flue-gas desulfurization. The flue gas passes through a s

crubber, and a slurry of wet calcium carbonate reacts with it to form carbon dioxide and calcium sulfite. The calcium sulfite then reacts with oxygen to form calcium sulfate, which is sold as gypsum.
(b) If the mole fraction of oxygen in air is 0.209, what volume (L) of air at 1.00 atm and 25°C is needed to react with all the calcium sulfite?
Chemistry
1 answer:
irakobra [83]1 year ago
6 0

So they tell us that we have four giggle years of flue gas and they're wanting us to find out how much calcium Sophia in kilograms we can obtain from this. So we know that one Giga Leader is equal to one time 10 to the nine leaders.

and they inform us that our stress is equal to one surroundings and that our temperature is equal to 25 degrees Celsius. i am just gonna add to seventy three Calvin to this. So our temperature goes to be 98. Calvin. All proper, so we are simply gonna plug the whole thing into our equation. So one atmosphere times our quantity so four times, 10 to the nine leaders. we're gonna divide this through ours. i'm just gonna use artwork zero.8 to 1 leader's atmosphere per mole, Kelvin.

and then we are gonna times that by way of our temperature. so to 98 Calvin. All right, so when we calculate this out, are moles of flue gasoline is gonna identical to one.6 35 instances generally tend to the 8 moles of our flue gasoline. So now that we've got our moles of flue gas, we need to find a connection between the most of flue fuel and the mass of our calcium selfie.

So if we pass up here, we see that one more of our silver dioxide is equal to at least one mole of our calcium sulfate. So we're gonna use that connection to help us discover the big calcium selfie. So we want to locate the moles of our sulfur dioxide and they provide us the mole fraction for silver dioxide. they say it's a thousand times that of clean air, and we recognize that the mole fraction for easy air is two instances 10 to the negative 10.

So our mole fraction to be able to is equal to two instances 10 to the poor, 10 times a thousand. So our new mole fraction for S 02 goes to be  instances 10 to the terrible seven. Hurry. And we realize our moles of sulfur dioxide are identical to its mole fraction times the full wide variety of moles. So we do recognise the full variety of moles.

it's what number of moles of our flue gas we have. So our moles of eso to is gonna be too  instances 10 to the negative seven instances 1.635 times tend to the 8 moles. So our moles of sulfur dioxide goes to be 32.7 moulds. So now that we've maximum of the sulfur dioxide, we are able to get the moles of our calcium, Sophie, and that's just gonna be the moles of our sulfur dioxide. And we're gonna times that by means of that one toe, one-mole ratio. So one mole, calcium Sophie to at least one-mole sulfur dioxide.

So the moles of our calcium sulphate is the same at 32.7 maximum. So now, to get the mass of our calcium selfie, we simply take our range of maximum of 32.7 moles. I worked inside the times that via its molar mass, that's 136.14 grams in keeping with mole.

So our mass of calcium sulfate is equal to four hundred or 4451.eight g. They need this in kilograms. Sword goes to divide this by way of hundreds. So when we do this, it is gonna equal 4 factors for 518 kilograms of our calcium. So toes and that is Thea amount or the mass of calcium sulphate we will get from four Giga leaders of flue gasoline.

All right, so for the second a part of this question, they're asking us the quantity of air needed to react with all the calcium sulphides. as a way to figure that out, we're gonna need to parent out the moles of 02 They do give us the mole fraction for 02 and it is identical to 0.2 09 after which we're searching out the quantity of air in leaders. All proper, so we recognize that moles of 02 are identical to its small fraction times the full moles of air So maximum of 02 is gonna be 0 factor 209 times all through moles of air.

So allow's simply use that variety for our Mueller ratio to discern out our moles of calcium sulphate. So we are gonna use 32.7 of our calcium, so fight as it's simply gonna be a 1 to one ratio. Oh, we recognize that for each 1.five moles of 02 we've one mole, our calcium sulfate. and then we also know that for each one mole of air, we've got zero.209 moles of 02 So we calculate this out. Are moles of air goes to same 78.2 moles of air?

So then, to get the volume we are simply gonna use PV is same to N. R. T. So we're solving for quantity. So n r t divided through the pressure. They tell us that the pressure is same to 1 environment and we are gonna be using a temperature equal to 2 98 Calvin.

So our extent is gonna identical 78.2 moles of air while times that through our cost of zero.8 to one leaders surroundings in keeping with greater Calvin or in times that fireplace temperature, which is to ninety eight Calvin, I might not divide all of this through one surroundings. So our extent of air is gonna identical to 1913 leaders of air this is had to react absolutely with calcium sulfate. and that's how we noticed the second part of this problem.

Learn more about calcium sulfate brainly.com/question/7962933

#SPJ4

You might be interested in
Which of the following are likely to form an ionic bond?
maria [59]

Answer:

B. Carbon and sulfur

Explanation:

8 0
3 years ago
The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C
artcher [175]

Explanation:

The given data is as follows.

         P_{1} = 100 mm Hg or \frac{100}{760}atm = 0.13157 atm

         T_{1} = 1080 ^{o}C = (1080 + 273) K = 1357 K

         T_{2} = 1220 ^{o}C = (1220 + 273) K = 1493 K

         P_{2} = 600 mm Hg or \frac{600}{760}atm = 0.7895 atm

          R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

                   log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}

            log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]

          log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]

                0.77815 = \frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K

              \Delta H_{vap} = 2.219 \times 10^{5} J/mol

                                   = 2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}

                                    = 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

4 0
3 years ago
Give the chemical symbol for the element with the ground‑state electron configuration [ Ar ] 4 s 2 3 d 1 . symbol: Determine the
Rus_ich [418]

Answer:

Sc (Scandium) has the given electronic configuration.

Explanation:

The given electronic configuration is [Ar]4s^{2}3d^{1}.

The last electron enters the d-subshell and hence is a d-block element known as Scandium with chemical symbol Sc.

For 4s subshell

n=4,l=0 and m ranges from -l to +l so m=0.

For 3d subshell

n=3,l=2 and m ranges from -l to +l so m can take values -2,-1,0,+1,+2

Note:

l values for subshells:

s : 0

p : 1

d : 2

f : 3 and so on.

5 0
3 years ago
Using the periodic table, choose the more reactive nonmetal.<br> Te or O
jolli1 [7]

the answer is Te because O is oxygen.

5 0
3 years ago
Read 2 more answers
How many moles of CO2 must dissolve in excess water to produce 12 moles of<br><br> H2CO3?
vodka [1.7K]

Answer:

12 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CO₂ + H₂O —> H₂CO₃

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Finally, we shall determine the number of moles of CO₂ that will dissolve in water to produce 12 moles of H₂CO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

Thus, 12 moles of CO₂ is required.

3 0
3 years ago
Other questions:
  • By mistake, you added salt instead of sugar to the oil. How can you remove the salt?
    7·2 answers
  • How does a lithium cation compare to a lithium atom?
    7·1 answer
  • Sulfuric acid (h2so4) is spilled on a laboratory bench. which chemical would be useful for neutralizing the acid
    13·1 answer
  • Suppose the amu had been defined as 110th of the mass of a phosphorus atom. What would be the relative mass of carbon-12?
    7·1 answer
  • 2) Os foguetes são utilizados para levar pessoas ao espaço (os astronautas), mas principalmente cargas como, por exemplo, os sat
    7·1 answer
  • 20 grams of H₂S react with 20 grams of O₂. What is the limiting reagent? *
    13·1 answer
  • Please help, I don't under stand! Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxi
    13·1 answer
  • Liquid is a state of matter characterized by ionized particles, no definite shape or volume, and good electrical conductivity? T
    12·1 answer
  • Which one are only compounds? *
    11·2 answers
  • (b)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!