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jarptica [38.1K]
3 years ago
9

(6x – 8) + (–x + 7)

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Step-by-step explanation:

6x-(-x)+8+7=5x+15

5x= 15

x=15÷5

x=3

PSYCHO15rus [73]3 years ago
6 0

Answer:

5x -1

Step-by-step explanation:

(6x – 8) + (–x + 7)

Combine like terms

6x -x   -8+7

5x -1

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Can someone help me with problem please? It’s special right triangle: decimal answers (Round to the nearest tenth)
DochEvi [55]

Answer:

h= 4.6, c=7.1

Step-by-step explanation:

First you need to know in a 30 60 90 triangle the sides ratios are x, 2x and x√3, and for 45 90 45 it is x, x and x√2

so <em>h</em> is 8/√3 and you rationalize the bottom so it becomes 8√3/3. when you solve this and round to nearest hundred it becomes 4.6. for the second one, it is 5√2 and when you solve this and round, it becomes 7.1

8 0
3 years ago
Which is the equation for the line perpendicular to y = –5/3 x + 11 1/3 and containing P(–2, 3)?
kati45 [8]
Okay, to answer this question, 
<span>Perpendicular lines have slopes that are inverse of one another and with opposite signs so, 
If a line has a slope of m= -2 than a perpendicular line will have slope m=1/2
If a line has a slope of m= -3/4 than a perpendicular line will have slope m=4/3 If a line has a slope of m= 6 than a perpendicular line will have slope m=-1/6

So, just find the slope of your line, using it, get the slope of the line that will be perpendicular and then just get the equation for a line that has that slope and passes through point (-2,3) using: y - y1 = m(x - x1)
I hope I helped you with my answer</span>
7 0
3 years ago
Answer number one please
tankabanditka [31]

Answer:

-3 + 6 = -3

Step-by-step explanation:

add the terms -3 and 6

exponent law

6 0
3 years ago
Read 2 more answers
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daser333 [38]
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3 years ago
Help!!!!! Not the top one by the way..!
OverLord2011 [107]

Answer:

\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}

3 0
3 years ago
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