ANSWER

and
e have
EXPLANATION


Let us make y the subject and call it equation (2)


We put equation (2) in to equation (1)



Simplify to get,


Divide both sides by 31,



We put this value in to equation (2) to get,


We collect LCM to obtain,


Answer:
169 meters
Step-by-step explanation:
52/4=13 (since it's a square you divide it by 4 because the sides are equal, so each side is 13 meters)
13^2=169 (to find the area you square the length of each side)
Answer:
MMVI=2006 M MEANS 1000 AND ONE MORE M MEANS 1000 TOTAL 2000 THEN VI IS THE NUMBER SIX 6
Answer:

Step-by-step explanation:
So we have the inequality:

Definition of Absolute Value:

Note that the sign is flipped in the second case because we multiplied by a negative.
Add 5 to both sides to both equations:

Merge:

And we're done!
All you have to do is substitute the 1 into the m for the mile ride:
C = 0.20(1) + 2.00 = 0.20 + 2.00 = 2.20
The charge for 1 mile ride is $2.20.