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3 years ago

Name the effects that microgravity has on the body.

2 answers:

7 0

Risks of kidney stones and bone fractures, microgravity may alter the ability of bones to heal after fractures. Long stays in space impact muscles.

LuckyWell [14K]3 years ago

3 0

Bone structure loss is not common do to lack of gravity

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Calculate the speed of the object from 5 seconds to 10 seconds. Show your work and don't forget to include the units. (HINT for

Serga [27]

Answer:

Given

mᴀ = mʙ = mᴄ = 62 kg

Fᴀ = 480N

Fʙ = 240 N

Fᴄ = 600 N

Asked

aᴀ, aʙ, aᴄ = ?

Solution

Based on the question, we know that the mass of road A, road B and road C are same. And, the formula of acceleration is

so, we can calculate the acceleration of road A, road B and road C.

• for road A

aᴀ = 7,7419 m/s²

aᴀ = 7,75 m/s²

• for road B

aʙ = 3,8709 m/s²

aʙ = 3,87 m/s²

• for road C

aᴄ = 9,6774 m/s²

aᴄ = 9,68 m/s²

Explanation:

6 0

4 years ago

A long, straight, horizontal wire carries a left-to-right current of 20 A. If the wire is placed in a uniform magnetic field of

serg [7]

Answer:

Explanation:

vertical magnetic field B_v = 4 x 10⁻⁵ T.

Magnetic field due to horizontal current at point 20 cm above

= (μ₀/4π ) x (2i / R)

= 10⁻⁷ x 2 x 20/ 20 x 10⁻²

= 2 x 10⁻⁵ T

It will act coming out of paper. Hence it will be normal to magnetic field given .

So resultant magnetic field

= √ (4² + 2²) x 10⁻⁵ T

= 4.47 X 10⁻⁵ T .

8 0

3 years ago

What is the number of wavelengths that pass a given point each second called?

denpristay [2]

Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles that pass a point in one second.

4 0

3 years ago

a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, fin

trapecia [35]

Answer:

a) $E_{p} = 0$

$E_{k} = 168.7 J$

$E_{m} = 168.7 J$

b) $E_{p} = 73.6 J$

$E_{k} = 95.8 J$

$E_{m} = 169.4 J$

c) $E_{p} = 169.2 J$

$E_{k} = 0$

$E_{m} = 169.2 J$

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

$E_{p} = mgh = 0$

The kinetic energy is:

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J$

And the mechanical energies:

$E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J$

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

$E_{p} = mgh = 1.5*9.81*5 = 73.6 J$

Now, to find the kinetic energy we need to calculate the speed at 5 m:

$v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9$

$v_{f} = \sqrt{126.9} = 11.3 m/s$

$E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J$

And the mechanical energies:

$E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J$

c) At its maximum height:

$v_{f}$ : is the final speed = 0

$h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m$

Now, the potential, kinetic and mechanical energies are:

$E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J$

$E_{k} = \frac{1}{2}mv^{2} = 0$

$E_{m} = 169.2 J + 0 = 169.2 J$

I hope it helps you!

7 0

3 years ago

Iron's ability to rust is not a physical property because

gtnhenbr [62]

The answer should be c

6 0

3 years ago

Read 2 more answers