times more stars are there in universe compared to human eye can see
<h3><u>
Solution:</u></h3>
Given that, conservative estimate of the number of stars in the universe is 
The average human can see about 3,000 stars at night with only their eyes
To find: Number of times more stars are there in the universe, compared to the stars a human can see
Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see
Then from given statement,
<em><u>Substituting given values we get,</u></em>
Thus times more stars are there in universe compared to human eye can see
That is not a trapezoid, it is a general quadrilateral. All 2-dimensional, 4-sided figures have an internal angle sum of 360 (triangles are 180). So if you assume angles P and Q are right, they are each equal to 90 degrees, for a total of 180.
Subtract: 360 - 180 = 180. We know that S + R must equal 180. If you subtract 180 - 65, you get 115, which is obtuse (greater than 90 degrees). This matches the drawing as the unknown angle is clearly greater than 90. So the answer is 115 degrees.
Answer:
The means differ by 1, but the ranges differ by 40.
Step-by-step explanation:
The mean for LaTesha's score is (92+45+67+36+80)/5= 64
The mean for Benards score is (63+68+62+69+53)/5= 63
The range for LaTeshas score is 92-36=56
The range for Benards score is 69-53=16
So, 64-63=1 and 56-16= 40
Answer:
Step-by-step explanation:
If x - 1 is a factor of the cubic, then 1 should result in 0 when you put it in the cubic for x. Does it?
f(1) = 2(1)^3 - 15(1)^2 + 22(1) + 15
f(1) = 2 - 15 + 22 + 15
f(1)= 24.
No the result is not zero. So x - 1 is not a factor.
However there must be something that makes this cubic go to zero. The easiest way to find it is to graph it.
The numbers that do make this zero are -0.5, 3, 5
Which mean that the factors are (2x+1)(x-3)(x - 5)
Answer:
First one
Step-by-step explanation:
3s=5s-6
