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mamaluj [8]
3 years ago
12

When hydrogen peroxide (H2O2) is added to potassium iodide (KI) solution, the hydrogen peroxide decomposes into water (H2O) and

oxygen (O2). The chemical equation for this decomposition reaction is:
2H2O2 → 2H2O + O2


In this reaction, the potassium iodide is needed for the reaction to happen, but it isn’t changed in the reaction and can be used again. What is the role of potassium iodide in this reaction?

A. Reactant

B. Product

C. Precipitate

D. Catalyst
Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

D. Catalyst

Explanation:

Because a Catalyst is a substance that causes or accelerates a chemical reaction without itself being affected.

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A 14.2% by mass HCl solution has a density of 1.1684 g/mL. What is the concentration of this solution in molarity?
snow_tiger [21]

Answer:

[HCl] = 4.54 M

Explanation:

14.2 % by mass is 14.2 g in 100 g of solution.

Let's calculate the moles of our solute, HCl

14.2 g / 36.45 g/mol = 0.389 mol

Molarity is mol/L (moles of solute in 1L of solution)

Let's determine the volume of solution with density

Solution density = Solution mass / Solution volume

Solution volume = Solution mass / Solution density

Solution volume = 100 g / 1.1684 g/mL → 85.6 mL

For molarity, we need the volume in L. Let's make the unit change.

85.6 mL . 1 L/1000mL = 0.0856L

Molarity is 0.389 mol / 0.0856L → 4.54 M

3 0
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How many hydrogen atoms are represented in the formula (CH3)2CH2?
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What is the rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂?​
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Answer:

1.274.

Explanation:

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<em>∨ ∝ 1/√M.</em>

where, ∨ is the rate of diffusion of the gas.

M is the molar mass of the gas.

<em>∨₁/∨₂ = √(M₂/M₁)</em>

∨₁ is the rate of effusion of the methane.

∨₂ is the rate of effusion of acetylene gas.

M₁ is the molar mass of methane (M₁ = 16.0 g/mol).

M₂ is the molar mass of acetylene (M₂ = 26.0 g/mol).

<em>∴ The rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂ = ∨₁/∨₂ = √(M₂/M₁) </em>= √(26.0 g/mol)/(16.0 g/mol) = <em>1.274.</em>

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Answer:

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