Draw structures from the following names, and determine which compounds are optically active:(c) 1,2-dibromo-2-methylbutane
1 answer:
The given compound 1,2-dibromo-2-methylbutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .
<h3>What is di-symmetry?</h3>Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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Answer:
The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²
Explanation:
The given parameters is as follows;
The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g
The required information = The number of formula units of potassium chloride (KCl)
The Molar Mass of KCl = 74.5513 g/mol
Therefore, we have;
1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units
Therefore;
0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units
From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.