Question

use the equation 2C4H10 +13O2-->8CO2+10H2O to find how many moles of oxygen would react with .425 mol C4H10

Answer 1

2C4H10 + 13O2  →  8CO2 + 10H2O Since the equation is balanced, we can set up a proportion: 13 moles of O2 react with 2 moles of C4H10x  moles of O2 react with 0.425 moles of C4H10 13 → 2x → 0.425 x = 13 * 0.425 / 2 = 2.7625 2.7625 moles of O2 react with 0.425 moles of C4H10 

Answer 2

Answer: 2.76 moles  of $O_2$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

According to stoichiometry :

2 moles of $C_4H_{10}$ combine with 13 moles of $O_2$

0.425 moles of $C_4H_{10}$ will combine with =$\frac{13}{2}\times 0.425=2.76moles$ of $O_2$

Thus 2.76 moles  of $O_2$ would react with 0.425 moles of $C_4H_{10}$