Most of the momentum is transferred to the ball on top. Since the collision in this situation is elastic, momentum is conserved, meaning the momentum of both balls before hitting the floor is equal to the momentum of both balls right after the collision.
Answer:
It will take 0.01 s or 10 ms
Solution:
As per the question:
Length of the packet, L = 1,000 bytes =
Distance, d = 2500 km =
Speed of propagation, s =
Transmission rate, R = 2 Mbps
Now,
Propagation time, t can be calculated as:
t = 10 ms
- In general, propagation time, t is given by:
- No, this delay is independent of the length of the packet.
- No, this delay is independent of the rate of transmission.
You can manage how the devices and wires are connected but there are no device or something to reduce it.
Answer: Option (b) is the correct answer.
Explanation:
The force of gravity acting on an object helps in determining the weight of an object. But a place where there will be no gravity or have zero gravitational pull then it means the person will be weightless.
For example, force of gravity on moon is zero which means any object or person on moon will be weightless.
On the other hand, when a child is in the air as she plays on a trampoline then it means gravitational pull form the earth is acting on it. So, it will definitely has some weight.
Similarly, a scuba diver exploring a deep-sea wreck is under the ground where there will be force of gravity. Hence, it will also have some weight.
Thus, we can conclude that an astronaut on the Moon is the person who is weightless.