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WITCHER [35]
3 years ago
8

A television sells for $700. Instead of paying the total amount at the time of the purchase, the same television can be bought b

y paying $200 down and $50 a month for
14 months. How much is saved by paying the total amount at the time of the purchase?
Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0
100 dollars would be saved because $50 for 14 months is 600 + the 200 they put down compared to 700 upfront it’s more by 100
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3/4 ÷ 1/2 what is the answer to this
Maksim231197 [3]
Dividing by a half is the same as multiplying by two. 3/4 multiplied by 2 is
1 \frac{1}{2}
or, in improper fraction form
\frac{3}{2}
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5 0
3 years ago
Help me find 8.25% of 399
LUCKY_DIMON [66]

Answer:

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6 0
2 years ago
4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Find positive integers that satisfy
tankabanditka [31]

9514 1404 393

Answer:

  (x, y, z) = (1, 2, 3)

Step-by-step explanation:

The equations that result from reduction to row-echelon form are ...

  x = 0.4 +0.2t

  y = 5.6 -1.2t

  z = t

Then t must have a value 5n+3 for 0 ≤ n < 1. That is, t=3.

  x = 0.4 +0.2(3) = 1

  y = 5.6 -1.2(3) = 2

  z = 3

The integers that satisfy are (x, y, z) = (1, 2, 3).

4 0
3 years ago
Read 2 more answers
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