Y’all I have no idea what to do-
2 answers:
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Answer:
a) F= 4 i + 4
j
b) Θ=11.3
c) The work done is 20
Step-by-step explanation:
a) ||F||=8, α=π/4
Fx=||F||·sin(π/4)=8·
Fy=||F||·cos(π/4)=8·
F=Fx i + Fy j = 4 i + 4
j
b) We can find the value of Θ using the equation:
cos(Θ)=
where:
D= 3 i + 2 j
F=4 i + 4
j
The dot product is defined as the sum of the products of the components of each vector as:
F · D=
||F||= 8
||D||=
Hence:
Θ=arccos()
Θ=arccos(0.981)
Θ= 11.3°
c) Work is equal to:
F · D= =28.3
Other way of obtainig the work is:
||F||||D||cos(Θ)
where:
||F||= 8
||D||=
Θ=11.3°
So, ||F||||D||cos(Θ)=8××cos(11.3°)=28.3
9514 1404 393
Answer:
- 7.5 ft
- 32.5 ft, 5 ft
- 10.7 ft
Step-by-step explanation:
a) The starting height is h(0) = 7.5 feet, the constant in the quadratic function.
The irrigation system is positioned <u> 7.5 </u> feet above the ground
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b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...
h(5) = (-5 +10)(5) +7.5 = 32.5 . . . feet
The spray reaches a maximum height of <u> 32.5 </u> feet at a horizontal distance of <u> 5 </u> feet from the sprinkler head.
__
c) The maximum distance will be √32.5 + 5 ≈ 10.7 ft.
The spray reaches the ground at about <u> 10.7 </u> feet away.
