B, 190.
First you find the area of the circle (pi times radius squared) however, since you are given diameter, you must find radius by dividing diameter by 2. So, your radius is 9, then you plug it into the formula and you get 254.5. After multiplying this by 0.75 because you only want to find 75 percent of the area, you get the answer of 191m
RS Bisects QT means, it cuts QT in two equal halves, so QP would be equal to PT, as it is an isosceles triangle, one other side would be equal as well, so RP is equal to PS, Now, by ASA, we conclude the both mentioned triangles in the figure are congruent.
Hope this helps!
D) 34/5 because 6(5) = 30 30+4=34 , so its 34/5
Answer:
m∠RQS = 72°
m∠TQS = 83°
Step-by-step explanation:
m∠RQS +m ∠TQS = m∠RQT
The two angles combine to make a larger angle
So
m∠RQS = (4x - 20)
m∠TQS = (3x + 14)
(4x - 20) + (3x + 14) = 155
Group the Xs and the constants
4x + 3x - 20 + 14 = 155
Combine like terms
7x - 6 = 155
Add 6 to both sides
7x = 161
Divide by 7 on both sides
x = 23
Check:
4(23) - 20 + 3(23) + 14 = 155
92 - 20 + 69 + 14 = 155
155 = 155
But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.
m∠RQS = 4(23) - 20 = 72°
m∠TQS = 3(23) + 14 = 83°
Checking:
72 + 83 = 155
