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3 years ago

10

10 joules of work (energy) is required to transfer 2 coulombs of charge from X to Y. What is the potential difference between th

ese two points?

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

5v

Explanation:

W = 10J ;Q = 2C ;V = ?

So,potential between x and y is 5v

Hope it will help you if not so please sorry.

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catapult’s lever holds a cannonball. The lever is attached to a tightly held rope. When the rope is released, the lever springs

Shalnov [3]

Answer:

Potential energy

Explanation:

Before release, the catapult has potential energy stored in a tension of torsion device in it. Normally a flexible bow like object that could be made of wood or of metal.

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3 years ago

Why are weight and mass used synonymously on earth?

Lisa [10]

Weight and mass are used synonymously on earth because the value of g is constant on the earth because the weight of a body is the amount of force exerted by the Earths gravity on an object of finite mass. And, the mass of an object gives the amount of matter in the body and is measured in kilograms.

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3 years ago

Tamsen is interested in history, and read that because of its regular period, the pendulum constituted the basis of the most acc

geniusboy [140]

We will apply the concept of period in a pendulum, defined as the product between 2 $\pi$ by the square root of the length over gravity, this is mathematically

$T = 2\pi \sqrt{\frac{L}{g}}$

Here,

T = Period

L = Length

g = Acceleration due to gravity

For the period to be 1 second, then we must look for the necessary length for such a requirement so

$1 = 2\pi \sqrt{\frac{L}{9.8}}$

$(\frac{1}{2\pi})^2 = \frac{L}{9.8}$

$L = 9.8(\frac{1}{2\pi})^2$

$L = 0.2482m$

The meter's length would be slight less than one-fourth of its current length. Also, the number of significant digits depends only on how precisely we know g, because the time has been defined to be exactly 1s.

Therefore the correct answer is C.

3 0

3 years ago

When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.

Akimi4 [234]

Mass=1167kg
Initial velocity=u=10m/s
Acceleration=a=4m/s^2
Work done=105J=W
Final velocity=v=?
Force=F
Distance=d

Apply Newton's second law

$\\ \tt\hookrightarrow F=ma$

$\\ \tt\hookrightarrow F=1167(4)=4668N$

Now

$\\ \tt\hookrightarrow W=Fd$

$\\ \tt\hookrightarrow d=\dfrac{W}{F}$

$\\ \tt\hookrightarrow d=\dfrac{105}{4668}$

$\\ \tt\hookrightarrow d=0.022m$

Now

d be s

According to third equation of kinematics

$\\ \tt\hookrightarrow v^2=u^2+2as$

$\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)$

$\\ \tt\hookrightarrow v^2=100+8(0.022)$

$\\ \tt\hookrightarrow v^2=100+0.176$

$\\ \tt\hookrightarrow v^2=100.176$

$\\ \tt\hookrightarrow v=10.001m/s$

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2 years ago

What are three examples of objects that are too big to be studied without models

zysi [14]

1.The entire Universe
2. The milky way
3.Time and Space
hoped this helped

4 0

3 years ago