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Andrej [43]
3 years ago
7

A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductiv

ity of 0.84 W/(m oC). The temperature in the house is 20.5 °C, and the temperature outside is 4 oC. How much heat is lost through this window in one minute? Don't use scientific notations
Physics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

 P = 5280 W

Explanation:

The conductivity of the materials determines that heat flows from the hot part to the cold part, the equation for thermal conductivity transfer is

    P = Q / t = k A (T_{h} -T_{c}) / L

Where k is the thermal conductivity of the glass 0.8 W / ºC, A the area of ​​the window, T the temperature and L is glass thickness

Let's calculate the window area

    A = l * a

    A = 2.0 1.0

    A = 2.0 m²

Let's replace

    L = 0.5 cm (1 m / 100 cm) = 0.005 m

    P = 0.8 2 (20.5 - 4) / 0.005

    P = 5280 W

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Part b)

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Since the ball and rod is an isolated system and there is no external force on it so by momentum conservation we will have

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here we also use angular momentum conservation

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v_o = (v_2 + d\omega) - v_1

so we have

\omega = \frac{v_o + v_1 - v_2}{d}

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M v_o d - M(v_o - \frac{m}{M}v_2)d = \beta mL^2(\frac{v_o + v_o - \frac{m}{M}v_2 - v_2}{d})

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(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})v_2 = \frac{2\beta mL^2v_o}{d}

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Part b)

Now we know that speed of the ball after collision is given as

v_1 = v_o - \frac{m}{M}v_2

so it is given as

v_1 = v_0 - \frac{m}{M}(\frac{\frac{2\beta mL^2v_o}{d}}{(md + \frac{\beta mL^2}{d}(1 + \frac{m}{M})})

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