Answer:
Radius of the outer most dark fringe is 2.65 cm
Solution:
As per the question:
Radius of curvature of the glass, r = 10.8 m
No. of dark fringes, n = 100
Wavelength of light,
Now,
To calculate the radius R of the outermost ring:
Radius of the dark fringe of nth order is given by:
Answer:
d = 146.2 m
increase
Explanation:
Using Energy Balance:
U_i + W = U_f
K_i + U_gi + W = K_f + U_fg
0 + m*g*h + F*d = 0.5*m*v_f^2
(900)*(9.81)*(50 sin (5)) + 400*50 = 0.5*900*v_f^2
v_f^2 = 129.944
v_f = 11.4 m/s at the bottom of the hill
U_i + W = U_f
K_i + U_gi + W = K_f + U_fg
0.5*m*v_i^2 - F*d = 0
0.5*900*129.944 = 400*d
d = 146.19 m
part b
Heavier car will gain greater momentum at the bottom of the hill and attain a higher velocity at the bottom; hence, the distance will increase.
Answer: increase
Answer:
Explanation:
Energy, as we have noted, is conserved, making it one of the most important physical quantities in nature. The law of conservation of energy can be stated as follows: Total energy is constant in any process. It may change in form or be transferred from one system to another, but the total remains the same.
Answer:
The answer is 62 (B)
Explanation:
Just took the pre-test
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