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Sonja [21]
3 years ago
5

Which equation shows how to rewrite the sum of 30 and 45 using their greatest common factor? 30 + 45 = 5(6 + 9) 30 + 45 = 15(2 +

3) 30 + 45 = 5(6) + 15(3) 30 + 45 = 5(6)(3)
Mathematics
1 answer:
ycow [4]3 years ago
7 0

Answer: 30 + 45 = 15(2 + 3)

Step-by-step explanation:

The greatest common factor for 30 and 45 will be gotten as follows:

Factor of 30 = 2 × 3 × 5

Factor of 45 = 3 × 3 × 5.

GCF = 3× 5 = 15

Therefore, the equation that shows how to rewrite the sum of 30 and 45 using their greatest common factor will be:

30 + 45 = 15(2 + 3)

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Read 2 more answers
What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1
andrew11 [14]
Step 1. Simplify \frac{1}{5} (x+5) to \frac{x+5}{5}

\frac{x+5}{5} = \frac{1}{4} (x-3)+1

Step 2. Simplify \frac{x+5}{5} to 1+ \frac{x}{5}

1+ \frac{x}{5} = \frac{1}{4} (x-3)+1

Step 3. Simplify \frac{1}{4} (x-3) to \frac{x-3}{4}

1+ \frac{x}{5} = \frac{x-3}{4} +1

Step 4. Cancel 1 on both sides

\frac{x}{5} = \frac{x-3}{4}

Step 5. Multiply both sides by 20 (the LCM of 5,4)

4x=5(x-3)

Step 6. Expand

4x=5x-15

Step 7. Subtract 5x from both sides

4x-5x=-15

Step 8. Simplify 4x-5x to -x

-x=-15

Step 9. Multiply both sides by -1

x=15

Done! :) Hope this helps! :)








3 0
3 years ago
sally gave her brother 3.95 in quarters and dimes. if the number of quarters is 6 more then the number of dimes, how many quarte
iragen [17]
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)

(2)->    q-d= 6
       q-d+d= 6+d
              q= 6+d...(2a)

(2a)-> (1)      0.25q+0.10d=3.95
              0.25(6+d)=0.10d= 3.95
           1.95+0.25d+0.10d= 3.95
                               0.35d= 3.95-1.5
                       0.35d/0.35= 2.45/0.35
                                      d= 7...(3)

(3)->(2)     q-d= 6
                 q-7= 6
                    q=6+7
                    q= 13
There are 13 quarters and 7 dimes.
7 0
3 years ago
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