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Sloan [31]
3 years ago
12

Hooke's law states that the force, F, in a spring extended by a length x is given by

Physics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

dimensions of k are  kg / s^2

Explanation:

F=ma   (Newton's second law)

F=-kx   (Hooke's law)

so equate both

-kx = ma

k = -ma/x

= mass * acceleration / distance  (dimensions, -1 has no dimension)

= kg * m/s^2 / m

= kg / s^2

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6) A stone is thrown vertically upward and returns to its starting position in o 5 s,What was its initial velocity?
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Read 2 more answers
A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial spe
dezoksy [38]

Answer:

the magnitude of the average contact force exerted on the leg is  3466.98 N

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Initial velocity of hand v₀ = 5.25 m/s

final velocity of hand v = 0 m/s

time interval t = 2.65 ms = 0.00265 s

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We calculate force on the hand F_{hand

using equation for impulse in momentum

F_{hand × t = m( v - v₀ )

we substitute

F_{hand × 0.00265  = 1.75( 0 - 5.25 )

F_{hand × 0.00265  = 1.75( - 5.25 )

F_{hand × 0.00265  = -9.1875

F_{hand = -9.1875 / 0.00265  

F_{hand = -3466.98 N

Next we determine force on the leg F_{leg

Using Newton's third law of motion

for every action, there is an equal opposite reaction;

so, F_{leg = - F_{hand

we substitute

F_{leg = - ( -3466.98 N )

F_{leg = 3466.98 N

Therefore, the magnitude of the average contact force exerted on the leg is  3466.98 N

5 0
3 years ago
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