Answer:
The last option, 20 N and 2.04 kg
Explanation:
work = (force)(distance)
work = 120 joules
distance: 6 m
rearrange to find force:
120=(6)F
F= 120/6 = 20 Newtons.
Assuming its lifted from Earth's surface, the force of gravity will be 9.81 m/s^2. Let's find mass:
F=mg
m=F/g
m=(20)/(9.81)= 2.038 kg
Answer:
velocity = 472 m/s
velocity = 52.4 m/s
Explanation:
given data
steady rate = 0.750 m³/s
diameter = 4.50 cm
solution
we use here flow rate formula that is
flow rate = Area × velocity .............1
0.750 =
× (4.50×
)² × velocity
solve it we get
velocity = 472 m/s
and
when it 3 time diameter
put valuer in equation 1
0.750 =
× 3 × (4.50×
)² × velocity
velocity = 52.4 m/s
Answer:
T = 92.8 min
Explanation:
Given:
The altitude of the International Space Station t minutes after its perigee (closest point), in kilometers, is given by:

Find:
- How long does the International Space Station take to orbit the earth? Give an exact answer.
Solution:
- Using the the expression given we can extract the angular speed of the International Space Station orbit:

- Where the coefficient of t is angular speed of orbit w = 2*p / 92.8
- We know that the relation between angular speed w and time period T of an orbit is related by:
T = 2*p / w
T = 2*p / (2*p / 92.8)
Hence, T = 92.8 min