We can use Triangle Inequality Theorem, the length of the third side of a triangle must always be between (but not equal to) the sum and the difference of the other two sides.
4.1 - 1.3 < x < 4.1 + 1.3
2.8 < x < 5.7
so, the answer is 2.8 < x < 5.7
1/3 is the slope
X= 12-6=6
Y= 4-2=2
I got the slope 1/3 I used the points (6,2), (12.4)
Answer:
The answers is "
Option B".
Step-by-step explanation:
Where,
predicted value of lead content when traffic flow is 15.
Calculating thet-critical value
The lower predicted value 
When 
of CI use as the expected lead content:
Two other ways to name plane V are
plane ANCRMX
plane XMRCNA
Answer:
a. 12 feet b. 12 feet 0.5 inches c. 8.33 %
Step-by-step explanation:
a. How far out horizontally on the ground will it protrude from the building?
Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.
So, by ratios rise/run = 1/12 = 12/x
1/12 = 12/x
x = 12 × 12
x = 144 inches
Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet
b. How long should the ramp be?
The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.
So, L = √(12² + 144²)
= √[12² + (12² × 12²)]
= 12√(1 + 144)
= 12√145
= 12 × 12.042
= 144.5 inches
Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches
c. What percent grade is the ramp?
The percentage grade of the ramp = rise/run × 100 %
= 12 inches/144 inches × 100 %
= 1/12 × 100 %
= 0.0833 × 100 %
= 8.33 %
