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Alisiya [41]
3 years ago
7

What is this pls help 3t+ 9 >= 15 ​

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

t >= 2.

Step-by-step explanation:

3t+ 9 >= 15

3t >= 15 - 9

3t >= 6

t >= 6/3

t >= 2.

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Speaker placement. a stereo receiver is in a corner of an 18​-ft by 24​-ft room. speaker wire will run under a​ rug, diagonally,
hoa [83]
The length of wire to be purchased will be found as follows:
c²=a²+b²
c²=18²+24²
c²=900
c=√900
c=30 ft
Thus the length of the wire will be:
30+4+4
=38 ft


6 0
2 years ago
Evaluate the integral. pls help me see the steps. thank you​
Alona [7]

Answer:

-\frac{2}{15}(1-x)^\frac{3}{2}(3x+2)+C

Step-by-step explanation:

Use the method of integration by parts. The method is based in the following rule of derivation of two functions f and g :

(fg)' = f'g+fg'\implies fg'=(fg)'-f'g\implies \\\int fg' dx = fg -\int f'g dx

Identify suitable f and g in the original expression. I use:

f=x\,\,\,, \,\,\,g=\sqrt{1-x}\\f'=1\,\,\,,\,\,\,g'=-\frac{2}{3}(1-x)^\frac{3}{2}

and write the integration by parts :

\int x\sqrt{1-x} dx = -\frac{2}{3}x(1-x)^\frac{3}{2}+\frac{2}{3}\int (1-x)^\frac{3}{2}dx=\\ =-\frac{2}{3}x(1-x)^\frac{3}{2}-\frac{4}{15}(1-x)^\frac{5}{2}+C=\\=-\frac{2}{15}(1-x)^\frac{3}{2}(3x+2)+C

with C an arbitrary integration constant.

8 0
2 years ago
Calculate a three-day weighted moving average for the price of the stock for the end of Day 7 where the most recent price has a
postnew [5]

The three-day weighted moving average for the price of the stock at the end of Day 7 is 57.17.

<h3>How do we calculate a weighted moving average?</h3>

Note that since this is for the end of Day 7, it implies that the actual Day 7 Stock Price is not yet known at the time of the calculation and we need to forecast it.

Therefore, the most recent price is Day 6 Sock Price and a three-day weighted moving average for this question can be calculated as follows:

Three-day weighted moving average = ((Day 6 Sock Price * 3) + (Day 5 Sock Price * 2) + (Day 4 Sock Price * 1)) / (3 + 2 + 1)

Three-day weighted moving average = ((55.00 * 3) + (59.00 * 2) + (60.00 * 1)) / (3 + 2 + 1)

Three-day weighted moving average = 57.17

Learn more about the weighted moving average here: brainly.com/question/19260285.

#SPJ1

4 0
1 year ago
Juan sells 2 sizes of dried wreaths it takes him 3 hours to make each large and 2 hours to make each small one. he has material
Karo-lina-s [1.5K]

Answer:  The answer is (2,9) and (6,3).


Step-by-step explanation: Given that Juan sells 2 sizes of dried wreaths. He takes 3 hours to make each large one and tales 2 hours to make each small one. Also, he has material for maximum 6 large wreaths or maximum 9 small wreaths.

Let, 'x' and 'y' be the number of number of large wreaths and number of small wreaths respectively made by Juan.

So, according to the given information, we have the following relations -

3x+2y\leq 24,~~x\leq 6,~~y\leq 9.

We tried plotting these inequalities in the graph paper (please see the attached figure), and found that the following two solutions will fit the situation perfectly.

Point A (x = 2, y = 9)   and   point B (x = 6, y = 3).

Thus, the two possible combinations are

(i) 2 large wreaths and 9 small wreaths, and

(ii) 6 large wreaths and 3 small wreaths.


7 0
3 years ago
A flagpole has a height of 16 yards. It will be supported by three cables, each of which is attached to the flagpole at a point
Marta_Voda [28]
Cables are forming 3 right angled triangles the pole being the shared height of them;

(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);

a^2 + b^2 = c^2

12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;

1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45

Add them up = 84yd of cable needed
8 0
3 years ago
Read 2 more answers
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