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storchak [24]
3 years ago
6

A survey was conducted to determine the amount of time, on average, during a given week SCAD students spend outside of class on

class work (projects, homework, and studying). The data shows: 5, 7, 11, 14, 18, 22 (in hours). Calculate the standard deviation by using the appropriate formula. Round your answer to three decimal places.
Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

Standard Deviation = 5.928

Step-by-step explanation:

a) Data:

Days  Hours spent  (Mean - Hour)²

1              5                61.356

2             7                34.024

3            11                  3.360

4           14                   1.362

5           18               26.698

6          22               84.034

6 days 77 hours,    210.834

mean

77/6 = 12.833    and 210.83/6 =  35.139

Therefore, the square root of 35.139 = 5.928

b) The standard deviation of 5.928 shows how the hours students spend outside of class on class work varies from the mean of the total hours they spend outside of class on class work.

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aniked [119]

Answer: 600 bushels of 10% alcohol content and 400 bushels of 15% alcohol content.

Step-by-step explanation:

Let we add x quantity of 10% of alcohol content and y quantity of 15% alcohol content for making 12% of alcohol content mixture.

Then according to the question, 10% of x + 15 % of y = 12% of 1000

⇒ 0.1x + 0.15y = 120

⇒ 10x + 15y = 1200

⇒ 2x +3y  = 2400 -------- (1)

And, x + y = 1000

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Equation 1) - equation 2)

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By putting the value of y in equation 1),

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5 0
2 years ago
Type the correct answer in the box. Use numerals instead of words if necessary use the /
Lorico [155]

Answer:

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3 0
3 years ago
Please work this out
cestrela7 [59]

Answer:

? = 85°

Step-by-step explanation:

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7 0
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4 0
3 years ago
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